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Vesnalui [34]
4 years ago
5

Am I correct?? HELP!!

Mathematics
1 answer:
Vladimir79 [104]4 years ago
4 0
I believe so, but I am not sure good a math soooo
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Step-by-step explanation:

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Identify the k-value that makes the relationship shown in the table below proportional.​
uysha [10]

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The relation is proportional if y=kx \:or\:k=\frac{y}{x}

Putting values of x and y to find k.

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For x =4 and y =2 k is: k=\frac{y}{x}=\frac{2}{4} =\frac{1}{2}

For x =6 and y = 3 k is: k=\frac{y}{x}=\frac{3}{6} =\frac{1}{2}

For x = 8 and y = 4 k is: k=\frac{y}{x}=\frac{4}{8} =\frac{1}{2}

For x =10 and y = 5 k is: k=\frac{y}{x}=\frac{5}{10} =\frac{1}{2}

So, The value of k that makes the relationship shown in the table below proportional is \mathbf{\frac{1}{2}}

5 0
3 years ago
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