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vodomira [7]
3 years ago
15

Find the GCF of the two numbers, and rewrite the sum of the two numbers using the distributive property.

Mathematics
1 answer:
Helen [10]3 years ago
8 0

Answer:

The GCF of 45 and 18 is 9

9(5+2)

(P.S. the sum of all of the number is 63)

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astraxan [27]

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The number sentence 4x7 =(4x3) +(4x4) is an example of what property ?
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I would say addition and multiplication.
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A movie theater charges $5 for an adult ticket and $2 for a child's ticket. One Saturday, the theater sold 785 tickets for $3280
Nadya [2.5K]

Answer:

5x + 2y = 3280

x+y = 785

x = 785 - y

5*(785 - y) + 2y = 3280

3925 - 5y + 2y = 3280

3925 - 3280 - 3y = 0

645 = 3y

y=645/3=215

x=785-215 = 570

Adults - 570 tickets, childs - 215 tickets.

570*5 + 215*2 = 3280

570 adult and 215 child and 3,280 in total

if i could get brainliest that would be great

6 0
3 years ago
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Candice leaves on a long trip driving at a steady rate of 35 miles per hour. Her sister Liz leaves from the same location travel
VARVARA [1.3K]

Answer:

<h2>D. 7h</h2>

Step-by-step explanation:

v=\dfrac{d}{t}\\\\v-\text{average speed}\\d-\text{distance}\\t-\text{time}\\\\d=vt,\ t=\dfrac{d}{v}\\\\\bold{Candice:}\ v_C=35\ mph,\ d_C,\ t_C\\\\\bold{Liz}:v_L=50\ mph,\ d_L,\ t_L=t-3\\\\\bold{Equation}:\\\\/\text{the distances are the same}/\\\\d_C=d_L\\\\d_C=v_Ct_C,\ d_L=v_Lt_L\\\\35t_C=50(t_C-3)\qquad\text{use the distributive property}\\\\35t_C=50t_C-150\qquad\text{subtract}\ 50t_c\ \text{from both sides}\\\\35t_C-50t_C=50t_C-50t_c-150\\\\-15t_C=-150\qquad\text{divide both sides by (-15)}

\dfrac{-15t_C}{-15}=\dfrac{-150}{-15}\\\\t_C=10\\\\t_L=10-3=7

4 0
3 years ago
Solve the equation. Check your answer. If necessary, round to 3 decimal places
Lana71 [14]

Answer:

x ≈ ±20.086/√(t - 1)  

Step-by-step explanation:

ln(t - 1) + ln(x²) = 6

Recall that lnu + lnv = ln(uv). Then  

ln(t - 1) + ln(x²) = ln[(t-1)x²] = 6

Take the natural antilogarithm of each side

(t - 1)x² = e⁶

Divide each side by t - 1

x² = e⁶/(t-1)

Take the square root of each side

x = ±e³/√(t - 1)

x ≈ ±20.086/√(t - 1)

6 0
3 years ago
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