Question

Nitrogen dioxide reacts with water to form nitric acid and nitrogen monoxide according to the equation: 3NO2(g)+H2O(l)→2HNO3(l)+NO(g) Part A Suppose that 4.2 mol NO2 and 0.50 mol H2O combine and react completely. Which reactant is in excess? Express your answer as a chemical formula. nothing

Answer 1

Answer: The excess reagent for a given reaction is nitrogen dioxide.

Explanation:

Limiting reagent is defined as the reagent which is present in less amount and also it limits the formation of products.

Excess reagent is defined as the reagent which is present in large amount.

For the given chemical reaction:

$3NO_2(g)+H_2O(l)\rightarrow 2HNO_3(l)+NO(g)$

By stoichiometry of the reaction:

1 mole of water reacts with 3 moles of nitrogen dioxide gas

So, 0.5 moles of water will react with = $\frac{3}{1}\times 0.5=1.5moles$ of nitrogen dioxide gas.

As, the given amount of nitrogen dioxide gas is more than the required amount. Thus, it is considered as an excess reagent.

Hence, nitrogen dioxide is an excess reagent.