Kc = [b]*[c]/([a]^2) = (0.2 M)^2/(0.2 M)^2 = 1.0
To achieve equilibrium, Kc must be equal to 0.2, therefore Kc must decrease, so the concentrations of b and c must decrease and the concentration of a must increase, meaning the reaction will proceed toward the formation of a.
Answer:
The correct answer is 4.58 grams.
Explanation:
Based on the Faraday's law of electrolysis, at the time of electrolysis, the amount of deposited substance is directly equivalent to the concentration of the flow of charge all through the solution. If current, I, is passed for time, t, seconds and w is the concentration of the substance deposited, then w is directly proportional to I*t or w = zIt (Here z refers to the electrochemical equivalent or the amount deposited when 1 C is passed).
For the reaction, n * 96500 C = molar mass
1C = molar mass/n*96500 = Equivalent wt / 96500
w = Equivalent wt / 96500 * I * t
In the given reaction,
Pb + PbO2 + 2HSO4- + 2H+ → 2PbSO4 + 2H2O, n = 2, the current or I drawn is 350 A, for time, t 12.2 seconds.
Now putting the values in the equation we get,
w = 207.19 / 2 * 96500 * 350 * 12.2 ( The molecular weight of Pb is 207.19 and the equivalent weight of Pb is 207.19 / 2)
w = 4.58 gm.
Answer:
Dipole, less electronegativity, higher electronegativity
Answer:
11.55 mol ≈ 11.6 mol CO2
Explanation:
C3H8 (g) + 5O2(g) → 3CO2 (g) + 4H2O(g)
from reaction 1 mol 3 mol
given 3.85 mol x mol
Solving proportion
x =(3.85*3)/1 = 11.55 mol ≈11.6 mol
Yes the correct answer is 3.14
