No, it won't. A substance will only precipitate if it is not soluble in an aqueous solution. If you look at the solubility rules, it indicates that all sulfates are soluble except for ions of Ba, Pb, Ca and Sr. Since Ag is not in the list, AgSO4 is soluble and will not precipitate.
The pH of a solution depicts the alkalinity or the acidity of the components of the solution and is given as a negative log function of hydrogen ions.
The pH of the solution is:
2
The pH can be estimated as:
![\rm pH= - log \;H^{+}](https://tex.z-dn.net/?f=%5Crm%20pH%3D%20-%20log%20%5C%3BH%5E%7B%2B%7D)
- Ionic equation of reaction is written as:
![\rm HCl = H^{+}+ Cl^{-}](https://tex.z-dn.net/?f=%5Crm%20HCl%20%3D%20H%5E%7B%2B%7D%2B%20Cl%5E%7B-%7D)
- The mole ratio between HCl and
= 1 : 1
- Concentration of
= 0.01 M
![\begin{aligned}\rm pH & = - \rm log \; 0.01\\\\&= 2 \end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%5Crm%20pH%20%26%20%3D%20-%20%5Crm%20log%20%5C%3B%200.01%5C%5C%5C%5C%26%3D%202%20%5Cend%7Baligned%7D)
Therefore, 2 is the pH of the solution.
To learn more about pH follow the link:
brainly.com/question/10270061
Answer: There are 0.056 moles present in 3.45 g of
.
Explanation:
Given : Mass = 3.45 g
Moles is the mass of substance divided by its molar mass.
Hence, moles of
(molar mass = 61.98 g/mol) is as follows.
![Moles = \frac{mass}{molar mass}\\= \frac{3.45 g}{61.98 g/mol}\\= 0.056 mol](https://tex.z-dn.net/?f=Moles%20%3D%20%5Cfrac%7Bmass%7D%7Bmolar%20mass%7D%5C%5C%3D%20%5Cfrac%7B3.45%20g%7D%7B61.98%20g%2Fmol%7D%5C%5C%3D%200.056%20mol)
Thus, we can conclude that there are 0.056 moles present in 3.45 g of
.
Answer:
c because they are the closest together