Answer:
3 seconds
Step-by-step explanation:
We have to give us the following function h (t) = - 16 * t ^ 2 + 48 * t + 3
Now, they tell us that the height is 3 feet, therefore replacing that value we have left:
3 = -16 * t ^ 2 + 48 * t + 3, operating cancels 3. And it would be:
-16 * t ^ 2 + 48 * t = 0
Removing common factor -16 * t, it would be:
(-16 * t) * (t - 3) = 0
We have two solutions:
-16 * t = 0 ---> t = 0
t - 3 = 0 ---> t = 3
Because the time cannot be 0 seconds, the time it would take the ball in the air is 3 seconds.
The answer is 4763. Hope that helped d:
Answer: When building a rocket, a rocket "defies" gravity. Usually, when you toss something in the air, you use force to go against gravity so the object won't fall immediately. So when a rocket scientist is essentially designing a rocket, they must take accountability that they have to use force to push the rocket in the air, hence, they are using Newton's Third Law of Motion.
Step-by-step explanation:
Answer:
I believe the answer you are looking for is "no"
