Answer:
C is the correct answe i need brainliest
Take the first 9 is in yours tens place so you want to take the second 9 and round up because anything 5 or more goes up and 4 or less stays the same
6/3 = 6 divided by 3
= 2
12/6= 12 divided by 6
= 2
Given:
circular merry-go-round that has a diameter of 15 feet.
Find: How much trim does he need to buy to put around the edge of the merry-go-round?
We need to find the circumference of the merry-go-round to get the measurement of the trim needed.
Circumference = π d
π = 3.14
d = diameter = 15 feet
Circumference = 3.14 * 15 feet
Circumference = 47.10 feet.
Mr. Osterhout needs to buy 47.10 feet of trim to put around the circular merry-go-round.
Answer:
![\text{The length of new room}=16.64\text{ feet}](https://tex.z-dn.net/?f=%5Ctext%7BThe%20length%20of%20new%20room%7D%3D16.64%5Ctext%7B%20feet%7D)
![\text{Area of the new room}=266.24\text{ feet}^2](https://tex.z-dn.net/?f=%5Ctext%7BArea%20of%20the%20new%20room%7D%3D266.24%5Ctext%7B%20feet%7D%5E2)
Step-by-step explanation:
We have been given that the Rumpart family is building a new room onto their house. The width of the new room will be 16 feet.
The length of the room will be 4% greater than the width. This means that length of new room will be 16 feet plus 4% of 16.
![\text{The length of new room}=16+(\frac{4}{100}*16)](https://tex.z-dn.net/?f=%5Ctext%7BThe%20length%20of%20new%20room%7D%3D16%2B%28%5Cfrac%7B4%7D%7B100%7D%2A16%29)
![\text{The length of new room}=16+(0.04*16)](https://tex.z-dn.net/?f=%5Ctext%7BThe%20length%20of%20new%20room%7D%3D16%2B%280.04%2A16%29)
![\text{The length of new room}=16+0.64](https://tex.z-dn.net/?f=%5Ctext%7BThe%20length%20of%20new%20room%7D%3D16%2B0.64)
![\text{The length of new room}=16.64](https://tex.z-dn.net/?f=%5Ctext%7BThe%20length%20of%20new%20room%7D%3D16.64)
Therefore, the expression
represents the length of new room and the length of new room is 16.64 feet.
Since we know that area of a rectangular shape is width times length.
![\text{Area of rectangle}=\text{Length*Width}](https://tex.z-dn.net/?f=%5Ctext%7BArea%20of%20rectangle%7D%3D%5Ctext%7BLength%2AWidth%7D)
![\text{Area of the new room}=16\text{ feet}\times 16.64\text{ feet}](https://tex.z-dn.net/?f=%5Ctext%7BArea%20of%20the%20new%20room%7D%3D16%5Ctext%7B%20feet%7D%5Ctimes%2016.64%5Ctext%7B%20feet%7D)
![\text{Area of the new room}=266.24\text{ feet}^2](https://tex.z-dn.net/?f=%5Ctext%7BArea%20of%20the%20new%20room%7D%3D266.24%5Ctext%7B%20feet%7D%5E2)
Therefore, the area of the new room will be 266.24 square feet.