Answer:
the first box
fourth box
fifth box and last box
Step-by-step explanation:
Answer:
6.35555556
Step-by-step explanation:
I ain't never seen two pretty best friends
Answer:
p ∈ IR - {6}
Step-by-step explanation:
The set of all linear combination of two vectors ''u'' and ''v'' that belong to R2
is all R2 ⇔
And also u and v must be linearly independent.
In order to achieve the final condition, we can make a matrix that belongs to 
using the vectors ''u'' and ''v'' to form its columns, and next calculate the determinant. Finally, we will need that this determinant must be different to zero.
Let's make the matrix :
![A=\left[\begin{array}{cc}3&1&p&2\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D3%261%26p%262%5Cend%7Barray%7D%5Cright%5D)
We used the first vector ''u'' as the first column of the matrix A
We used the second vector ''v'' as the second column of the matrix A
The determinant of the matrix ''A'' is
We need this determinant to be different to zero
The only restriction in order to the set of all linear combination of ''u'' and ''v'' to be R2 is that
We can write : p ∈ IR - {6}
Notice that is 
⇒
If we write 
, the vectors ''u'' and ''v'' wouldn't be linearly independent and therefore the set of all linear combination of ''u'' and ''b'' wouldn't be R2.
First we find the slope between the two given points.
m = (y2 - y1)/(x2 - x1) = (-5 - 2)/(7 - 6) = -7/1 = -7
Now we use the slope-intercept equation of a line.
y = mx + b
We use one point as x and y, and we solve for b.
2 = -7(6) + b
2 = -42 + b
b = 44
The equation is
y = -7x + 44
Answer: f(x) = -7x + 44
The answer for this problem is 2 since it is not specified whether it is adjacent to the right or adjacent to the left.
If it is adjacent to the right, the answer is:
p (k) = 2 * p(1) + 2 * k
If the is adjacent to the left, the answer is:
P (k) = 2 *p(1) +2 * (k-2)
