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Fiesta28 [93]
3 years ago
7

Helllllp >_< Compare: 1.2057 O 1.1421

Mathematics
1 answer:
vladimir2022 [97]3 years ago
6 0

Answer:

Widal Kit Salmonella Ha, Hb, Hc, Hd, OA, OB, OC, OD

Rapid Labs Widal antigen set contains ready to use concentrated smooth antigen suspensions of the bacilli; S. typhi ‘O’. S. typhi ‘H’. S, paratyphi ‘AO’. S. paratyphi ’BO‘. S. paratyphi ’AH’, S. paratyphi ‘BH’. S. paratyphi ‘CH’. S. paratyphi ‘CO’ and/or polyspecific positive control reactive with these antigens.

When the Widal antigen suspensions are mixed and incubated with the patient’s serum, anti salmonella antibodies present in the patient serum react with the antigen suspensions to give agglutination. Agglutination is a positive test result, indicating presence of anti-salmonella antibodies in the patient serum. No agglutination is a negative test result indicating absence of anti-salmonella antibodies.

Pack size – 8 x 5ml

This kit does NOT contain positive and negative controls

Widal Kit Salmonella Ha, Hb, Hc, Hd, OA, OB, OC, OD

Rapid Labs Widal antigen set contains ready to use concentrated smooth antigen suspensions of the bacilli; S. typhi ‘O’. S. typhi ‘H’. S, paratyphi ‘AO’. S. paratyphi ’BO‘. S. paratyphi ’AH’, S. paratyphi ‘BH’. S. paratyphi ‘CH’. S. paratyphi ‘CO’ and/or polyspecific positive control reactive with these antigens.

When the Widal antigen suspensions are mixed and incubated with the patient’s serum, anti salmonella antibodies present in the patient serum react with the antigen suspensions to give agglutination. Agglutination is a positive test result, indicating presence of anti-salmonella antibodies in the patient serum. No agglutination is a negative test result indicating absence of anti-salmonella antibodies.

Pack size – 8 x 5ml

This kit does NOT contain positive and negative control

Step-by-step explanation:

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George and Cameron went on a bicycle trip.They took a bus to the starting point, and then biked the rest. They traveled 275 km i
EastWind [94]

In this type of problem, we would want to use a system of linear equations.

First, we need to find our equations. We know that the two boys traveled 275 km in total, and since x and y count the distance traveled (just in different modes of travel), we can write: x + y = 275.

Next, the problem says that they biked 55 km more than they bussed. So, x = y + 55.

Now that we have two equations to solve for two variables, we can lay them out next to each other:

x + y = 275

x = y + 55

We see that we can substitute x in the first equation with y + 55. This gives us

(y + 55) + y = 275

We solve for y and get y = 110 km by bus. But, we want to know how far they traveled by bike. So, since x = y + 55 and y = 110, we can solve for x by doing 110 + 55 = 165 km by bike.

The answer is 165 kilometers.

4 0
4 years ago
What rational number equals 0.6 with bar over 6?
Neko [114]

when you dive the fractions

2/3 = 0.666666

6/10=0.6000

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6/5 = 1.2

so the answer would be 2/3

8 0
4 years ago
HELP ME PLEASE I NEED THIS &lt;3333
WITCHER [35]

Answer:

214°

Step-by-step explanation:

The arc subtending an angle at the centre are equal, that is

arc ED = 90° and

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Thus

arc EDF = arc ED + arc DF = 90° + 124° = 214°

4 0
3 years ago
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Pavlova-9 [17]
If -2i is a root, then 2i is also a root. If √10 is a root, then -√10 is also a root. Convert all four of these roots into factors using the factor theorem (which says that if R is a root, then (x - R) is a factor). (x + 2i) (x - 2i) (x - √10) (x + √10) Multiply these factors together. (It's easiest to multiply the conjugate pairs together first.): x^4 - 6x^2 - 40
8 0
3 years ago
⦁ Convert the vertex form of the equation you wrote above to standard form.
Bond [772]

Answer:

ax^2 + bx + c

Step-by-step explanation:

im pretty sure this answers your question

3 0
3 years ago
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