Considering that the addresses of memory locations are specified in hexadecimal.
a) The number of memory locations in a memory address range ( 0000₁₆ to FFFF₁₆ ) = 65536 memory locations
b) The range of hex addresses in a microcomputer with 4096 memory locations is ; 4095
<u>applying the given data </u>:
a) first step : convert FFFF₁₆ to decimal ( note F₁₆ = 15 decimal )
( F * 16^3 ) + ( F * 16^2 ) + ( F * 16^1 ) + ( F * 16^0 )
= ( 15 * 16^3 ) + ( 15 * 16^2 ) + ( 15 * 16^1 ) + ( 15 * 1 )
= 61440 + 3840 + 240 + 15 = 65535
∴ the memory locations from 0000₁₆ to FFFF₁₆ = from 0 to 65535 = 65536 locations
b) The range of hex addresses with a memory location of 4096
= 0000₁₆ to FFFF₁₆ = 0 to 4096
∴ the range = 4095
Hence we can conclude that the memory locations in ( a ) = 65536 while the range of hex addresses with a memory location of 4096 = 4095.
Learn more : brainly.com/question/18993173
Answer:
minus 5 by 7
Step-by-step explanation:
5 - 7 = -2
2 - 3 = -1
The smaller the negative integer, the bigger the number.
Answer:
To convert a percent to a decmil just multiply the percent by 0.01
84*0.01=0.84
0.84
Hope This Helps!!!
Answer:
g(x) has a greater y intercept than f(x)
Step-by-step explanation:
f(x) = 6x^2 + 18x +3
f(0) = 0+0+3
The y intercept is 3
g(x) crosses the y axis at 6
The y intercept is 6
g(x) has a greater y intercept than f(x)
