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hammer [34]
3 years ago
7

Red Riding Hood is making a food basket out of 8 different fruits and 9 different vegetables. If there is only room for 6 items,

how many ways could there be an equal number of fruits & veggies? (You can show your process if you like; half mark possible. Avoid spaces.)
Mathematics
1 answer:
Bogdan [553]3 years ago
6 0

Answer:

169,344

Step-by-step explanation:

Data provided in the question

Different fruits = 8

Different vegetables = 9

There is only room for 6 items

Based on the above information, the number of ways for an equal number of fruits & veggies is

For the number of combinations of fruit is

= 8\times7\times6

For the number of combinations of vegetables is

= 9\times8\times7

So, the total combinations are

= 9\times8\times8\times7\times7\times6

= 169,344

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In which town does the total number have meaning
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2 years ago
A building company bids on two large projects. The CEO believes the chance of winning the 1st is 0.6, the chance of winning the
Ksju [112]

Answer:

0.8

Step-by-step explanation:

A: P(1) = .6, P(2) = .5, P(1 and 2) = .3

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3 years ago
5. (03.02 MC)
inn [45]

Answer:

f(4) =2

Step-by-step explanation:

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Let x=4

f(4) = 2 (4)^2 -30

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6 0
2 years ago
Which answer is equivalent to<br> ??? Help please
grigory [225]

Answer:

\large\boxed{\dfrac{36}{25}}

Step-by-step explanation:

\text{Use}\ a^{-n}=\dfrac{1}{a^n}\\\\\dfrac{5^{-2}\cdot9}{2^4\cdot4^{-3}}=(5^{-2}\cdot9):(2^4\cdot4^{-3})=\left(\dfrac{1}{5^2}\cdot9\right):\left(2^4\cdot(2^2)^{-3}\right)\\\\\text{use}\ (a^n)^m=a^{nm}\\\\=\left(\dfrac{1}{25}\cdot9\right):(2^4\cdot2^{-6})\\\\\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=\dfrac{9}{25}:2^{4+(-6)}=\dfrac{9}{25}:2^{-2}=\dfrac{9}{25}:\dfrac{1}{2^2}=\dfrac{9}{25}:\dfrac{1}{4}=\dfrac{9}{25}\cdot\dfrac{4}{1}=\dfrac{36}{25}

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3 years ago
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