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2 years ago

8

Peter paid $9.75 to go to the movies, which was $46.25 less than he paid to go to a concert. How much did he pay for the concert

?

1 answer:

Levart [38]2 years ago

3 0

Answer:

He payed 56 dollars for the concert.

Step-by-step explanation:

46.25 + 9.75= 56

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F(x) = 4x - 9 step by step and put the right anwser so I can read it

butalik [34]

<h2>f = -5</h2><h3></h3><h3>f(x) = 4x - 9</h3><h3>Add 9 to both sides</h3><h3>f(x) + 9 = 4x</h3><h3>Divide x from both sides</h3><h3>f + 9 = 4</h3><h3>Subtract 9 from both sides</h3><h3>f = -5</h3><h3></h3><h3><em>Please let me know if I am wrong.</em></h3>

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2 years ago

Find the product. 7/10 X 3/6

tiny-mole [99]

7 . 3
--- × ------
10. . 6

= 21
--------
60

= 7/20

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2 years ago

Evaluate f(x) = x2 – 12 when x = 5

Ede4ka [16]

Answer:

f(5) = 13

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

<u>Algebra I</u>

Function notation and substitution

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = x² - 12

x = 5

<u>Step 2: Evaluate</u>

Substitute: f(5) = 5² - 12
Exponents: f(5) = 25 - 12
Subtract: f(5) = 13

4 0

3 years ago

Read 2 more answers

A colony of bacteria is growing at a rate of 0.2 times its mass. Here time is measured in hours and mass in grams. The mass of t

11Alexandr11 [23.1K]

Answer:

<u>Question 1:</u> $dm/dt=0.2m$ <u />

<u />

<u>Question 2:</u> $m=Ae^{(0.2t)}$ <u />

<u />

<u>Question 3:</u> $m=10e^{(0.2t)}$ <u />

<u />

<u>Question 4:</u> $m=10g$ <u />

Explanation:

<u>Question 1: Write down the differential equation the mass of the bacteria, m, satisfies: m′= .2m</u>

<u></u>

a) By definition: $m'=dm/dt$

b) Given: $rate=0.2m$

c) By substitution: $dm/dt=0.2m$

<u>Question 2: Find the general solution of this equation. Use A as a constant of integration.</u>

a) <u>Separate variables</u>

$dm/m=0.2dt$

b)<u> Integrate</u>

$\int dm/m=\int 0.2dt$

$ln(m)=0.2t+C$

c) <u>Antilogarithm</u>

$m=e^{0.2t+C}$

$m=e^{0.2t}\cdot e^C$

$e^C=A\\\\m=Ae^{(0.2t)}$

<u>Question 3. Which particular solution matches the additional information?</u>

<u></u>

Use the measured rate of 4 grams per hour after 3 hours

$t=3hours,dm/dt=4g/h$

First, find the mass at t = 3 hours

$dm/dt=0.2m\\\\4=0.2m\\\\m=4/0.2\\\\m=20g$

Now substitute in the general solution of the differential equation, to find A:

$m=Ae^{(0.2t)}\\\\20=Ae^{(0.2\times 3)}\\\\A=20/e^{(0.6)}\\\\A=10.976$

Round A to 1 significant figure:

A = 10.

<u>Particular solution:</u>

$m=10e^{(0.2t)}$

<u>Question 4. What was the mass of the bacteria at time =0?</u>

Substitute t = 0 in the equation of the particular solution:

$m=10e^{0}\\\\m=10g$

3 0

2 years ago

1/2 + (-3/4)= <br> i need help /:

Marysya12 [62]

Start by converting to like terms, so convert 1/2 to 2/4.

Next, look at the problem. You are adding a negative, which is the same as subtracting, so your new problem looks like this: 2/4 - 3/4.

If you take 3/4 from 2/4, you are left with -1/4. This is your final answer!

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2 years ago