<h2>f = -5</h2><h3></h3><h3>f(x) = 4x - 9</h3><h3>Add 9 to both sides</h3><h3>f(x) + 9 = 4x</h3><h3>Divide x from both sides</h3><h3>f + 9 = 4</h3><h3>Subtract 9 from both sides</h3><h3>f = -5</h3><h3></h3><h3><em>Please let me know if I am wrong.</em></h3>
7 . 3
--- × ------
10. . 6
= 21
--------
60
= 7/20
Answer:
f(5) = 13
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
<u>Algebra I</u>
- Function notation and substitution
Step-by-step explanation:
<u>Step 1: Define</u>
f(x) = x² - 12
x = 5
<u>Step 2: Evaluate</u>
- Substitute: f(5) = 5² - 12
- Exponents: f(5) = 25 - 12
- Subtract: f(5) = 13
Answer:
- <u>Question 1:</u>
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- <u>Question 2:</u>
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- <u>Question 3:</u>
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- <u>Question 4:</u>
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Explanation:
<u>Question 1: Write down the differential equation the mass of the bacteria, m, satisfies: m′= .2m</u>
<u></u>
a) By definition: 
b) Given: 
c) By substitution: 
<u>Question 2: Find the general solution of this equation. Use A as a constant of integration.</u>
a) <u>Separate variables</u>

b)<u> Integrate</u>


c) <u>Antilogarithm</u>



<u>Question 3. Which particular solution matches the additional information?</u>
<u></u>
Use the measured rate of 4 grams per hour after 3 hours

First, find the mass at t = 3 hours

Now substitute in the general solution of the differential equation, to find A:

Round A to 1 significant figure:
<u>Particular solution:</u>

<u>Question 4. What was the mass of the bacteria at time =0?</u>
Substitute t = 0 in the equation of the particular solution:

Start by converting to like terms, so convert 1/2 to 2/4.
Next, look at the problem. You are adding a negative, which is the same as subtracting, so your new problem looks like this: 2/4 - 3/4.
If you take 3/4 from 2/4, you are left with -1/4. This is your final answer!