The answer to your question is Y=12
Answer:
The answer to your question is: Japan
Step-by-step explanation:
Mobile cost in Spain = € 352.5
Mobile cost in Japan = ¥39856
Exchange rate = £1 = €1.41
£1 = ¥188
Cost of mobile in pounds
£ 1 ------------------ € 1.41
x ----------------- €352.5
x = (352.5 x 1) / 1.41
x= £250
£1 ------------------ ¥188
x ----------------- -¥ 39856
x = (39856 x 1) / 188
x = £212
Then, it was cheaper in Japan
Answer:
Whole numbers are all natural numbers including 0 e.g. 0, 1, 2, 3, 4…
Integers include all whole numbers and their negative counterpart e.g. …-4, -3, -2, -1, 0,1, 2, 3, 4,…
Step-by-step explanation:
Answer:
$146410
Step-by-step explanation:
The formula for calculating future value:
FV = P (1 + r)^n
FV = Future value
P = Present value
R = interest rate
N = number of years
100,000 x (1.1)^4 = $146410
Well this is simple a calculator type problem...but if you are curious as the the algorithm used by simple calculators and such...
They use a Newtonian approximation until it surpasses the precision level of the calculator or computer program..
A newtonian approximation is an interative process that gets closer and closer to the actual answer to any mathematical problem...it is of the form:
x-(f(x)/(df/dx))
In a square root problem you wish to know:
x=√n where x is the root and n is the number
x^2=n
x^2-n=0
So f(x)=x^2-n and df/dx=2x so using the definition of the newton approximation you have:
x-((x^2-n)/(2x)) which simplifies further to:
(2x^2-x^2+n)/(2x)
(x^2+n)/(2x), where you can choose any starting value of x that you desire (though convergence to an exact (if possible) solution will be swifter the closer xi is to the actual value x)
In this case the number, n=95.54, so a decent starting value for x would be 10.
Using this initial x in (x^2+95.54)/(2x) will result in the following iterative sequence of x.
10, 9.777, 9.774457, 9.7744565, 9.7744565066299210578124802523397
The calculator result for my calc is: 9.7744565066299210578124802523381
So you see how accurate the newton method is in just a few iterations. :P
