We're not supposed to help with exams. This isn't an exam, is it?
A(0)=202, A(37)=half that.


Last choice.
The residual value is -1.14.
Plug 5 into x
y=-0.7(5)+2.36
=-1.14
Answer:
y = 2/5x + 18.
Step-by-step explanation:
The line will have the same slope of 2/5.
Using the point-slope form of a line:
y - 12 = 2/5(x - -15)
y - 12 = 2/5(x + 15)
y = 2/5x + 6 + 12
y = 2/5x + 18.
Correct Question: If m∠JKM = 43, m∠MKL = (8x - 20), and m∠JKL = (10x - 11), find each measure.
1. x = ?
2. m∠MKL = ?
3. m∠JKL = ?
Answer/Step-by-step explanation:
Given:
m<JKM = 43,
m<MKL = (8x - 20),
m<JKL = (10x - 11).
Required:
1. Value of x
2. m<MKL
3. m<JKL
Solution:
1. Value of x:
m<JKL = m<MKL + m<JKM (angle addition postulate)
Therefore:

Solve for x


Subtract 8x from both sides


Add 11 to both sides


Divide both sides by 2


2. m<MKL = 8x - 20
Plug in the value of x
m<MKL = 8(17) - 20 = 136 - 20 = 116°
3. m<JKL = 10x - 11
m<JKL = 10(17) - 11 = 170 - 11 = 159°
Take ln to both sides
ln 14^x = ln 5
then you'll get
x ln 14 = ln 5
divide both sides by ln 14
x = 0.6098533345
after rounding
x = 0.6099