Question

For the point P (-17,25) and Q(-10,30), fins the distance d(P,Q) and the coordinates of the midpoint M of the segment PQ.

Answer 1

Answer:

Distance = 8.6

M = (-13.5,27.5)

Step-by-step explanation:

Distance = $\sqrt{(x_{2 }- x_{1 })^2 + (y_{2 }- y_{1 })^2$

= $\sqrt{(-10_ }- (-17)_{ })^2 + (30_{ }- 25_{ })^2$

= $\sqrt{(-10_{ }+ 17_{ })^2 + 5^2_$

= $\sqrt{7^2+5^2}$

= $\sqrt{49+25}$

= $\sqrt{74}$

= 8.6

Midpoint = $(\frac{x_{2}+x_{1}}{2};\frac{y_{2}+y_{1}}{2})$

= (-10+(-17)) ÷ 2 ; (30+25) ÷ 2

= -27 ÷2 ; 55 ÷ 2

= -13.5, 27.5