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dimaraw [331]
3 years ago
15

Which of the following polynomials have like terms?

Mathematics
1 answer:
Artyom0805 [142]3 years ago
4 0
It should be 37y4+6y^2-2y^2+y-1
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Indica el valor del 3 en cada uno de los siguientes números 35.097 _ 753.978 _ 7.543 _ 312.501
lara31 [8.8K]
Free points pls and thank you
5 0
3 years ago
REUPLOAD!! (Worth 10 Points Each I Believe.) (please zoom / zoom out if needed to see question. (: )
irakobra [83]
I'm trying to help you in a easy way. Just multiply the numbers for part 1. And then add the numbers u multiplied from part 1 all together and you will have your answer for part 2. Lol don't report this because i am not good at multiplying so ye but this is what i would have done.<span />
5 0
3 years ago
Read 2 more answers
Given the function below, if f(x) = -1, find
dmitriy555 [2]

Answer:

x = -3

Step-by-step explanation:

f(x) = 4x + 11

f(x) = -1

Substitute -1 for f(x)

-1 = 4x + 11

Subtract 11

-12 = 4x

Divide by 4

-3 = x

x = -3

6 0
2 years ago
40 points plz help if u can Which function has no Zeroes? Select all that apply.
Damm [24]
<h3>2 Answers: Choice C and choice D</h3>

y = csc(x) and y = sec(x)

==========================================================

Explanation:

The term "zeroes" in this case is the same as "roots" and "x intercepts". Any root is of the form (k, 0), where k is some real number. A root always occurs when y = 0.

Use GeoGebra, Desmos, or any graphing tool you prefer. If you graphed y = cos(x), you'll see that the curve crosses the x axis infinitely many times. Therefore, it has infinitely many roots. We can cross choice A off the list.

The same applies to...

  • y = cot(x)
  • y = sin(x)
  • y = tan(x)

So we can rule out choices B, E and F.

Only choice C and D have graphs that do not have any x intercepts at all.

------------

If you're curious why csc doesn't have any roots, consider the fact that

csc(x) = 1/sin(x)

and ask yourself "when is that fraction equal to zero?". The answer is "never" because the numerator is always 1, and the denominator cannot be zero. If the denominator were zero, then we'd have a division by zero error. So that's why csc(x) can't ever be zero. The same applies to sec(x) as well.

sec(x) = 1/cos(x)

7 0
2 years ago
If 15 mi = 8 km, about how many miles would be equal to 50 km?
Anon25 [30]
Use ratios to solve

15 m/8 km = x m/50 km Cross multiply
15(50) = 8x
750 = 8x divide by 8 on both sides
93.75 = x

93.75 miles = 50km
6 0
3 years ago
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