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Marat540 [252]
3 years ago
7

Is 0.3x (4 - y) and - 1.2x - 0.3y equivalent

Mathematics
1 answer:
guapka [62]3 years ago
6 0

Answer:

Inconsistent

Step-by-step explanation:

We are given the equations;

0.3y=0.6x+0.3

1.2x+0.6=0.6y

Assuming we are required  to determine whether the system of equations are consistent or inconsistent  

We are going to use substitution

Making y the subject;

Equation 1: 0.3y=0.6x+0.3

Dividing both sides by 0.3

y = 2x + 1

Equation 2: 1.2x+0.6=0.6y

Dividing both sides by 0.6

y = 2x + 1

This means both equations are similar and we can't get a solution.

Therefore, the system of equations is inconsistent.

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An angle that measures between 90° and 180° is called a(n)_____ angle.
jeka57 [31]
The answer is B. obtuse
7 0
3 years ago
Read 2 more answers
How do you check? <br> -5r+-3=51
Varvara68 [4.7K]

-5r + (-3) = 51

Add 3 to both sides:

-5r = 54

Divide both sides by -5 to get r alone:

r = -10.8

To check this, plug in -10.8 into the equation: -5(-10.8) + (-3) = 51

54 + (-3) = 51

54 - 3 = 51

51 = 51

This statement is true, so the answer is correct.

5 0
3 years ago
Jana ran the first 3 and a half miles of a 5 mile race in 1 3rd of an hour. what was her average rate, in mph, for the first par
Lisa [10]

Answer:

always try to draw a diagram first

Step-by-step explanation:

Jana ran The first 3.5 miles in 1/3 of an hour. remember the problem tells us that we want our answer in miles per hour or mph. so we have to set up our problem so that our units match in the end. The diagram above shows 3.5 mi over 1/3 hour. so we must divide 3.5 miles by 1/3 hour

note:

3 \frac{1}{2} mi =  \frac{7mi}{2}

therefore

\frac{7mi}{2}  \:  \div  \:  \frac{1hr}{3}  =

\frac{7mi}{2}  \times  \frac{3}{1hr}  =  \frac{21mi}{2hr}  = 10 \frac{1}{2}  \frac{mi}{hr}

7 0
3 years ago
All the members of a construction crew work at the same pace. Six of them working together are able to pour foundation in 22 hou
Ksivusya [100]
Draw a picture if you are a visual person if not then just do 22 divided by 2 and I got 11hrs
7 0
4 years ago
Read 2 more answers
Answer asap please
Oduvanchick [21]

Answer:

(0,1) and (-2,9)

Step-by-step explanation:

A point (x,y) lies on the graph of f(x) = (\frac{1}{3} )^{x} if it satisfies the condition y = (\frac{1}{3} )^{x}

<h3>(0,1):</h3>

        x = 0 and y = 1.

This point satisfies the required condition as

        (\frac{1}{3} )^{0} = 1

Hence, this point <u>is</u> on the graph of f(x) = (\frac{1}{3} )^{x}

<h3>(3,27):</h3>

        x = 3 and y = 27.

This point doesn't satisfy the required condition as

        (\frac{1}{3} )^{3} = \frac{1}{27} ≠ 27

Hence, this point i<u>s not</u> on the graph of f(x) = (\frac{1}{3} )^{x}

<h3>(-2,9):</h3>

        x = -2 and y = 9.

This point satisfies the required condition as

        (\frac{1}{3} )^{-2} = 3^{2} = 9

Hence, this point <u>is</u> on the graph of f(x) = (\frac{1}{3} )^{x}

<h3>(-1,-\frac{1}{3}):</h3>

        x = -1 and y = -\frac{1}{3}.

This point satisfies the required condition as

        y = (\frac{1}{3} )^{-1} = 3^{1} = 3 ≠ -\frac{1}{3}

Hence, this point <u>is not</u> on the graph of f(x) = (\frac{1}{3} )^{x}

7 0
3 years ago
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