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3 years ago

Identify whether each cube root or square root lies between 2 and 3, 4 and 5, or 9 and 10.

Mathematics

1 answer:

leva [86]3 years ago

3 0

Answer:

The cube root and square root are not given, but I'm going to give a chart that might help.

Square roots:

2 = √4

3 = √9

4 = √16

5 = √25

9 = √81

10 = √100

Cube roots:

2 = ^3√8

3 = ^3√27

4 = ^3√64

5 = ^3√125

9 = ^3√729

10 = ^3√1000

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Rewrite 14/36 in simplest form.

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3 years ago

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Alexeev081 [22]

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2 years ago

Here are the first five terms of a sequence.

Snezhnost [94]

Step-by-step explanation:

3 to 8= 5

8 to 17= 9

17 to 30= 13

30 to 47= 17

47 to 68= 21

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93 to 122= 29

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solve by

$2 {n}^{2} - n + 2 \\ 2 {(9)}^{2} - 9 + 2 \\ 2(81) - 9 + 2 \\ 162 - 9 + 2 \\ 153 + 2 = 155$

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3 years ago

Simplify the expression

finlep [7]

Answer:

$\frac{2*x - 2}{2*x} - \frac{3*x + 2}{4*x} = \frac{x - 6}{4*x}$

Step-by-step explanation:

We have the expression:

$\frac{2*x - 2}{2*x} - \frac{3*x + 2}{4*x}$

The first thing we want to do, is to have the same denominator in both equations, then we need to multiply the first term by (2/2), so the denominator becomes 4*x

We will get:

$(\frac{2}{2} )\frac{2*x - 2}{2*x} - \frac{3*x + 2}{4*x} = \frac{4*x - 4}{4*x} - \frac{3*x + 2}{4*x}$

Now we can directly add the terms to get:

$\frac{4*x - 4}{4*x} - \frac{3*x + 2}{4*x} = \frac{4*x - 4 - 3*x - 2}{4*x} = \frac{x - 6}{4*x}$

We can't simplify this anymore

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3 years ago

On Monday jack could lift 25lbs

kirill [66]

Answer:

he can still lift 25 or more

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3 years ago