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emmasim [6.3K]
3 years ago
8

The volume of a box is 80 cubic feet with length x-3 and width x-1 and height x+5. What are the possible values of x? What are t

he possible dimensions?

Mathematics
1 answer:
Kryger [21]3 years ago
4 0

Answer:

  • the only possible value of x is 5
  • the dimensions are 2 × 4 × 10

Step-by-step explanation:

The cubic equation ...

  (x -3)(x -1)(x +5) = 80

has one real root: x = 5. Using that value for x, the dimensions become ...

  length = 5 - 3 = 2

  width = 5 - 1 = 4

  height = 5 + 5 = 10

The dimensions are (length, width, height) = (2, 4, 10).

_____

We cannot tell the thrust of the problem, since it has only one solution. Perhaps you're supposed to write the cubic in standard form and use the <em>Rational Root theorem</em> to find <em>possible values of x</em>. That form can be found to be ...

  (x -3)(x -1)(x +5) -80 = 0

  x³ +x² -17x -65 = 0

Descartes' rule of signs tells you there is one positive real root. The rational root theorem tells you possible rational roots are factors of 65:

  1, 5, 13, 65

We know that x must be greater than 3 (so all dimensions are positive). Thus <em>possible values of x are 5, 13, 65</em>, and we're pretty sure that 65 is way too large.

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What do i say for this <br> please help :((((
Ostrovityanka [42]

Answer:

Step-by-step explanation:

Error 1) It should be divided by 5.

x - 5 = 0

x = 5

Error 2) -3   15   0    -1     5

coefficient of x² is 0 and it is not included

3 0
2 years ago
In a 50-gram portion of cereal, 8 grams of it are sugar . Which of the following represents the percent of the 50-grams that is
andre [41]

Answer:

3) 16

8 is 16% of 50

4 0
3 years ago
Show your work 2 1/5 × 3 1/8
vesna_86 [32]

Solution

For this case we can do the following:

2\cdot\frac{1}{5}=\frac{2\cdot5+1}{5}=\frac{11}{5}3\cdot\frac{1}{8}=\frac{3\cdot8+1}{8}=\frac{25}{8}

And then if we multiply we got:

\frac{11}{5}\cdot\frac{25}{8}=\frac{55}{8}

4 0
1 year ago
Replace ? with an expression that will make the equation valid.
AlexFokin [52]

Answer:

4x³

Step-by-step explanation:

d/dx ln(x⁴ + 7) = 1/(x⁴ + 7) × _?

To obtain the missing expression, let us simplify d/dx ln(x⁴ + 7). This can be obtained as follow:

Let y = ln (x⁴ + 7)

Let u = (x⁴ + 7)

Therefore,

ln(x⁴ + 7) = ln u

Thus,

y = ln u

dy/du = 1/u

Next, we shall determine du/dx. This is illustrated below:

u = (x⁴ + 7)

du/dx = 4x³

Finally, we shall determine dy/dx of ln (x⁴ + 7) as follow:

dy/dx = dy/du × du/dx

dy/du = 1/u

du/dx = 4x³

dy/dx = 1/u × 4x³

But:

u = (x⁴ + 7)

Therefore,

dy/dx = 1/(x⁴ + 7) × 4x³

Thus, the missing expression is 4x³

6 0
3 years ago
8 times of the eight term of an arithmetic progression is equal to 12 times of the twelfth term. find its first term if the comm
denpristay [2]

Answer:

38

Step-by-step explanation:

We can express the 8th term as x and the 12th term as y.

This would mean that 8x=12y

Because the common difference between terms is -2 and term 8 and term 12 are 4 terms apart, this means that the 12th term is 8 less than the 8th term, so x-8=y

Now we can use this to substitute y with x in the first equation. This would give us:

8x=12(x-8)

Which we can expand and solve:

8x=12x-96

-4x=-96

Therefore x=24

This means the 8th term is 24 and the 12th term is 16 (24-8).

To test if this is correct we can do:

8x24=12x16

Which indeed are equal, both sides multiply to 192.

Now that we have our 8th term, we can find the 1st term, which is 7 terms away, therefore we just add 14 to the 8th term 24. (7x2=14)

24+14=38.

The first term is 38.

Hope this helped!

3 0
3 years ago
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