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2 years ago

7) One track coach wants his athletes to race 5 miles around a track to measure how fast

1 answer:

5 0

Five laps? I don’t know if you meant to put that the track is a mile around, but if the track is a half mile around, an athlete would have to run 10 laps around the track to run 5 miles.
X=5/y, so x would be how many laps the athletes run, and y would be the length of the track. Hope this helps

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Two wires are attached 6 feet up a tree and 3 feet from the base of the tree. About how much TOTAL wire was used?

nalin [4]

Answer:

9 cm²

Step-by-step explanation:

Two wires are attached 6 feet up a tree and 3 feet from the base of the tree. About how much TOTAL wire was used?

We solve the above question, using the Area of a Triangle

Area = 1/2 × Base × Height

Area = 1/2 × 3 × 6

Area = 9 cm²

Therefore, the total wore that was used was 9cm² of wire

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3 years ago

10x + 9y=0<br> 8x + 18y=0

Luba_88 [7]

Answer:

x=0 y=0

Step-by-step explanation:

multiple the first equation by 2

after subtract equation 2 from 1

after getting x you substitute the value of x in any of the equation for your y

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2 years ago

Plzz answer this as soon as possible! The graph shows the number of miles two cars travel.

Solnce55 [7]

The answer is 15

From the graph:
Car A traveled 60 miles in one hour
Car B traveled 75 miles in one hour.

Car B travels 15 more miles per hour

3 0

2 years ago

One - eighth of 7.92 x 10^10

liraira [26]

The answer is 9900000000 (thats 8 zeros) What you do is you find 10^10 which is 10000000000 (ten zeros) and multiply that by 7.92 to get 79200000000 then you just multiply it by 1/8 to get the answer.

3 0

3 years ago

Blake is playing a racing game on his computer. The game tracks the locations of objects using and y coordinates (see graph belo

Anvisha [2.4K]

<h3>Answer: 2.2 units</h3>

============================================

Explanation:

I'll define these point labels

B = Blake's starting position
F = finish line
C = the third unmarked point of the triangle

The locations of the points are

B = (-8,1)
C = (-6,-3)
F = (4,-2)

Use the distance formula to find the distance from B to C

$B = (x_1,y_1) = (-8,1) \text{ and } C = (x_2,y_2) = (-6,-3)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(-8-(-6))^2 + (1-(-3))^2}\\\\d = \sqrt{(-8+6)^2 + (1+3)^2}\\\\d = \sqrt{(-2)^2 + (4)^2}\\\\d = \sqrt{4 + 16}\\\\d = \sqrt{20} \ \text{ ... exact distance}\\\\d \approx 4.47214 \ \ \text{... approximate distance}\\\\$

Segment BC is roughly 4.47214 units long.

Following similar steps, you should find that segment CF is approximately 10.04988 units long.

If Blake doesn't take the shortcut, then he travels approximately BC+CF = 4.47214+10.04988 = 14.52202 units. This is the path from B to C to F in that order.

---------

Use the distance formula again to find the distance from B to F. This distance is about 12.36932 units. He travels this amount if he takes the shortcut.

Subtract this and the previous result we got

14.52202 - 12.36932 = 2.1527

That rounds to 2.2

This is the amount of distance he doesn't have to travel when he takes the shortcut.

In other words, the track is roughly 2.2 units shorter when taking the shortcut.

Side note: Replace "units" with whatever units you're working with (eg: feet or meters).

7 0

2 years ago