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Temka [501]
3 years ago
7

7) One track coach wants his athletes to race 5 miles around a track to measure how fast

Mathematics
1 answer:
Lady bird [3.3K]3 years ago
5 0
Five laps? I don’t know if you meant to put that the track is a mile around, but if the track is a half mile around, an athlete would have to run 10 laps around the track to run 5 miles.
X=5/y, so x would be how many laps the athletes run, and y would be the length of the track. Hope this helps
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Write a power represented with a positive base and a positive exponent whose value is less than the base
Murrr4er [49]
That's <u>always</u> true if <em>either</em> the exponent <em>or </em>the base is less than ' 1 '.

(But not always of they both are.)
7 0
3 years ago
The family of solutions to the differential equation y ′ = −4xy3 is y = 1 √ C + 4x2 . Find the solution that satisfies the initi
slega [8]

Answer:

The correct option is 4

Step-by-step explanation:

The solution is given as

y(x)=\frac{1}{\sqrt{C+4x^2}}

Now for the initial condition the value of C is calculated as

y(x)=\frac{1}{\sqrt{C+4x^2}}\\y(-2)=\frac{1}{\sqrt{C+4(-2)^2}}\\4=\frac{1}{\sqrt{C+4(4)}}\\4=\frac{1}{\sqrt{C+16}}\\16=\frac{1}{C+16}\\C+16=\frac{1}{16}\\C=\frac{1}{16}-16

So the solution is given as

y(x)=\frac{1}{\sqrt{C+4x^2}}\\y(x)=\frac{1}{\sqrt{\frac{1}{16}-16+4x^2}}

Simplifying the equation as

y(x)=\frac{1}{\sqrt{\frac{1}{16}-16+4x^2}}\\y(x)=\frac{1}{\sqrt{\frac{1-256+64x^2}{16}}}\\y(x)=\frac{\sqrt{16}}{\sqrt{{1-256+64x^2}}}\\y(x)=\frac{4}{\sqrt{{1+64(x^2-4)}}}

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8 0
3 years ago
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5 0
3 years ago
Find the next three terms in the sequence 625, 250, 100, 40...
pentagon [3]
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To solve this, let's divide

625/250 = 2.5

So is the pattern.. x/2.5 = x2/2.5 = x3/2.5...

We can test this theory by multiplying

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Since 250 comes before 100 in the sequence then our theory is correct!

So to find the next numbers, divide:

40/2.5 = 16
16/2.5 = 6.4
6.4 = 2.56

The answer is C.

Hope this helps! :)
6 0
3 years ago
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