All categories

3 years ago

Can you show me how you worked this: Evaluate the expression. 9! − 7!

Mathematics

1 answer:

Aloiza [94]3 years ago

3 0

I hope this helps you

9.8.7!-7!

7! (72-1)

7!.71

You might be interested in

90°<br> 30<br> x help me with this work

ehidna [41]

Answer:

90°

Step-by-step explanation:

$x + 90 \degree = 180 \degree \\ (linear \: pair \: \angle s) \\ \therefore \: x = 180 \degree - 90 \degree \\ x = 90 \degree$

6 0

3 years ago

If 24 extra large cans of soup will serve 96 people, how many cans should Ann buy to serve 28 people?

klio [65]

Answer:

She should buy a total of 25, so one more can

4 0

3 years ago

The measure of two complementary angles are in the ratio 1 : 5. What are the degree measures of the two angles? What is the solu

ser-zykov [4K]

Ratio 1:5....added = 6
complimentary angles, when added, = 90 degrees

1/6(90) = 90/6 = 15
5/6(90) = 450/6 = 75

so ur 2 angles are : 15 and 75

3 0

2 years ago

Read 2 more answers

How many triangles and quadrilaterals altogether can be formed using the vertices of a 7-sided regular polygon?

MAVERICK [17]

Answer: The correct option is

(E) 70.

Step-by-step explanation: We are given to find the number of triangles and quadrilaterals altogether that can be formed using the vertices of a 7-sided regular polygon.

To form a triangle, we need any 3 vertices of the 7-sided regular polygon. So, the number of triangles that can be formed is

$n_t=^7C_3=\dfrac{7!}{3!(7-3)!}=\dfrac{7\times6\times5\times4!}{3\times2\times1\times4!}=35.$

Also, to form a quadrilateral, we need any 4 vertices of the 7-sided regular polygon. So, the number of quadrilateral that can be formed is

$n_q=^7C_4=\dfrac{7!}{4!(7-4)!}=\dfrac{7\times6\times5\times4!}{4!\times3\times2\times1}=35.$

Therefore, the total number of triangles and quadrilaterals is

$n=n_t+n_q=35+35=70.$

Thus, option (E) is CORRECT.

8 0

3 years ago

A number n, decreased by 10

Anettt [7]

Answer:

n - 10

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers