Given : Two inequality is given to us . The inequality is v + 8 ≤ -4 and v - 6 ≥ 10 .
To Find : To write those two inequality as a compound inequality with integers .
Solution: First inequality given to us is v + 8 ≤ -4 . So let's simplify it ;
⇒ v + 8 ≤ -4 .
⇒ v ≤ -4 - 8.
⇒ v ≤ -12 .
Now , on simplifying the second inequality ,
⇒ v - 6 ≥ 10 .
⇒ v ≥ 10 + 6.
⇒ v ≥ 16 .
Hence the required answer will be :
First one implies that v is less than or equal to -12 whereas the second one implies that v is greater than or equal to 16 .
Answer:
a.) Between 0.5 and 3 seconds.
Step-by-step explanation:
So I just went ahead and graphed this quadratic on Desmos so you could have an idea of what this looks like. A negative quadratic, and we're trying to find when the graph's y-values are greater than 26.
If you look at the graph, you can easily see that the quadratic crosses y = 26 at x-values 0.5 and 3. And, you can see that the quadratic's graph is actually above y = 26 between these two values, 0.5 and 3.
Because we know that the quadratic's graph models the projectile's motion, we can conclude that the projectile will also be above 26 feet between 0.5 and 3 seconds.
So, the answer is a.) between 0.5 and 3 seconds.
Answer is 20.3 and the steps are:
1.) 7 x 9 = 63 move the six over the 2 leave the 3 down
2.) 7 x 2 = 14
3.) 14 + 6 = 20
4.) you have 203 but must bring the decimal down and it makes it: 20.3
I hope I helped and if you're confused please ask questions
Answer
4000
900
0
7
Step-by-step explanation:
Not so sure about the answer though
