Wah..I need to ask my bro to answer this.. Brb
Answer:
2
Step-by-step explanation:
substitute n=1 and n=3 in the given equation
1 st term is (1)^2-1-2 = 1 -1 -2 = -2
3rd term is (3)^2-3-2 = 9-3-2=4
sum of 1st and 3rd term is -2 + 4 = 2
84/2 = 42
42/2 = 21
21/3 = 7
7/7 = 1
84 = 2^2 * 3 * 7
I believe it is D if i’m correct
Eliminate y's
multiply second equaiton by 4
4x+4y=-4
add to first equation
3x-4y=-24
<u>4x+4y=-4 +</u>
7x+0y=-28
7x=-28
divide both sides by 7
x=-4
sub back
x+y=-1
-4+y=-1
add 4 to both sides
y=3
(x,y)
(-4,3)
D is answer
