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2 years ago

BRAINLEST HELPPP ME PLZZZZZZZZZZZZZ

Mathematics

2 answers:

klasskru [66]2 years ago

7 0

We aren’t going to be able to help :( it’s to much

Ira Lisetskai [31]2 years ago

5 0

Answer:

its a project which is hard to show on brainly.

Step-by-step explanation:

Sorry I cant help this time

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I will give brainliest!! THERE IS NO OTHER INFORMATION GIVEN!! In ⊙O, chord XY is 8 cm long and is 10 cm from O. What is the rad

Zielflug [23.3K]

Answer:

radius ≈ 10.77 cm

Step-by-step explanation:

The segment from the centre O to the chord is a perpendicular bisector.

Thus 2 right triangles are formed with legs 10 cm and 4 cm ( half of XY )

The radius r is the hypotenuse.

Using Pythagoras' identity, then

r² = 4² + 10² = 16 + 100 = 116 ( take the square root of both sides )

r = $\sqrt{116}$ ≈ 10.77 cm ( to 2 dec. places )

4 0

3 years ago

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Identify the polygon with vertices A(5,0), B(2,4), C(−2,1), and D(1,−3), and then find the perimeter and area of the polygon. HE

inn [45]

Answer:

Part 1) The polygon is a square

Part 2) The perimeter is equal to $20\ units$

Part 3) The area is equal to $25\ units^{2}$

Step-by-step explanation:

we have

$A(5,0), B(2,4), C(-2,1),D(1,-3)$

Plot the points

see the attached figure

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance AB

$A(5,0),B(2,4)$

substitute in the formula

$d=\sqrt{(4-0)^{2}+(2-5)^{2}}$

$d=\sqrt{(4)^{2}+(-3)^{2}}$

$d=\sqrt{25}$

$AB=5\ units$

Find the distance BC

$B(2,4), C(-2,1)$

substitute in the formula

$d=\sqrt{(1-4)^{2}+(-2-2)^{2}}$

$d=\sqrt{(-3)^{2}+(-4)^{2}}$

$d=\sqrt{25}$

$BC=5\ units$

Find the distance CD

$C(-2,1),D(1,-3)$

substitute in the formula

$d=\sqrt{(-3-1)^{2}+(1+2)^{2}}$

$d=\sqrt{(-4)^{2}+(3)^{2}}$

$d=\sqrt{25}$

$CD=5\ units$

Find the distance AD

$A(5,0),D(1,-3)$

substitute in the formula

$d=\sqrt{(-3-0)^{2}+(1-5)^{2}}$

$d=\sqrt{(-3)^{2}+(-4)^{2}}$

$d=\sqrt{25}$

$AD=5\ units$

we have that

AB=BC=CD=AD

Find the distance BD (diagonal)

$B(2,4),D(1,-3)$

substitute in the formula

$d=\sqrt{(-3-4)^{2}+(1-2)^{2}}$

$d=\sqrt{(-7)^{2}+(-1)^{2}}$

$BD=\sqrt{50}\ units$

Verify if the polygon is a square

If the triangle BDA is a right triangle, then the polygon is a square

Applying the Pythagoras theorem

$BD^{2}=AD^{2}+AB^{2}$

substitute

$(\sqrt{50})^{2}=5^{2}+5^{2}$

$50=50$ -----> is true

The triangle BDA is a right triangle

therefore

The polygon is a square

Find the Area of the polygon

The area of a square is equal to

$A=b^{2}$

we have

$b=5\ units$

$A=5^{2}=25\ units^{2}$

Find the perimeter of the polygon

The perimeter of a square is equal to

$P=4b$

we have

$b=5\ units$

$P=4(5)=20\ units$

6 0

2 years ago

Find the function's range. Enter your answer in interval notation

DerKrebs [107]

Answer:

its subject matter about eco

Step-by-step explanation:

mark brainlist pzz✌️

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2 years ago

Can you please answer this question

Nat2105 [25]

Answer:

1. b

2. a

3. d

4. c

Step-by-step explanation:

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3 years ago

When the outliers are removed, how does the mean change? dot plot with 1 on 50, 1 on 76, 1 on 78, 2 on 79, 1 on 80, 1 on 81, 2 o

sveticcg [70]

We can plot this data on MS Excel and determine the distribution of these data reflected on the graph. Among these numbers, 50 is the outlier since it is very far from the other numbers ranging from 76 to 83. We can perform interquartile range to determine or verify the outliers in the data set. In this respect, we can see that there is not much distribution seen. The average of all data sets is equal to 96.25. When the outlier (50) is removed, we expect the mean to become higher since a low number was ommitted including high numbers only. Outliers are obtained from special causations such as human errors.

5 0

2 years ago

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