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katovenus [111]
3 years ago
14

Would it be? (6, 5) Will give a thanks :)

Mathematics
1 answer:
Tatiana [17]3 years ago
3 0
I think it would be (6,5) So sorry if it wrongs
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Scientific notation of a length of 0.0000923
Tju [1.3M]

Answer:

9.23 x 10^-5

Step-by-step explanation:

But the decimal point behind the first number that isn't 0

Then count how many times you moved it and that is the exponent on the ten

If you moved the decimal right, it is negative exponent

If you moved the decimal left, it is a positive exponent

5 0
3 years ago
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Factorise fully<br>-12a - 16 <br><br>please do quick, first to answer marked brainiest!!​
Allushta [10]

Answer:

-4( 3a+4)

Step-by-step explanation:

-12a - 16

-4*3a -4*4

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3 0
3 years ago
What’s the differential equation of
worty [1.4K]

Answer:

y=\frac{1}{x^{2}-6x+13 }

Step-by-step explanation:

We have given,

                        \frac{dy}{dx}=y^{2}(6-2x)

and initial condition x=3,\  y=\frac{1}{4}

Now,

\frac{dy}{dx}=y^{2}(6-2x)

Rearranging the variables, we get

\frac{dy}{y^{2} }=(6-2x).dx

Applying integration both sides, we get

\int\ {\frac{dy}{y^{2} } } \,=\int\ {(6-2x).} \, dx

⇒\frac{-1}{y} =6x-\frac{2x^{2} }{2}

⇒ \frac{-1}{y}=6x-x^{2}  +C                  

Putting the initial condition (i.e., x=3,\  y=\frac{1}{4}), we get

⇒ -4=6\times3-(3)^{2}+C

⇒ -4=18-9+C

∴ C=-13

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now putting the value of C in above equation, we get

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⇒  \frac{1}{y}=-6x+x^{2}  +13

y=\frac{1}{x^{2}-6x+13 }

5 0
3 years ago
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Mamont248 [21]

Answer:

I think the answer is 12.

5 0
3 years ago
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balu736 [363]

Answer:

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4 0
3 years ago
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