Answer: the rate at which its altitude is changing is -47 ft/s
Step-by-step explanation:
Given that;
ds/dt = 45 mph = 45 × 5280/3600 = 66 ft/sec
no we have to determine dx/dt
so
cos∅ = dx/dt / ds/dt
cos45° = dx/dt / 66
dx/dt = 0.7071 × 66
dx/dt = 46.6686 ≈ 47 ft/s ( as altitude is decreasing, its negative - )
so the rate at which its altitude is changing is -47 ft/s
The correct answer is D
The equation of a circle is (x-h)^2 + (y-k)^2 = r^2
to find (h,k), you find the middle of the circle, in this scenario you do so by finding the middle of the diameter, a line that goes through the center of the circle.
To find the X value of the midpoint, add both x values together and divide by 2 and repeat for y
-13 + -1 = -14
-14/2 =-7
10+ -6 = 4
4/2 = 2
therefore (h,k) = ( -7, 2 )
Next plug these values in the equation of a circle
(x-h)^2 + (y-k)^2 = r^2
becomes
(x- (-7)) ^2 + (y-(2)) ^2 = r^2
to find r, use the distance formula to find the length of the diameter, 20, and divide by 2
plug 10 in for r and you get 100
(x+7)^2 + (y-2)^2 = 100
sorry for the late response
Answer:
(a) h^-1(x) = (x+6)/6
Step-by-step explanation:
The inverse relation can be found by solving for y: x = h(y).
<h3>Solution</h3>
x = h(y) . . . . . the inverse relation
x = 6y -6 . . . . . use the function definition
x +6 = 6y . . . . add 6
(x +6)/6 = y . . . . divide by 6
The inverse function is ...
The <em>approximate increase</em> in Area of the parking lot is about 133%
Area of a rectangle = Length × width
<u>Initial Area of parking lot</u> :
- 75 feets × 150 feets = 11250 ft²
<u>New Area of parking lot</u> :
Width = 75 + 100 = 175 feets
Length = 150 feets
Area = 175 × 150 = 26250 ft²
<u>Percentage increase in </u><u>Area</u><u> </u><u>of lot</u> :
((16250 - 11250) / initial Area) × 100%
(15000 / 11250) × 100% = 133.33%
Therefore, the <em>approximate increase</em> on area of lot is 133%
Learn more : brainly.com/question/18109354
sin(0) = opposite/hypotenuse = 2/5
cos(0) = adjacent/hypotenuse = sqrt21/5
tan(0) = opposite/adjacent = 2/sqrt21 * sqrt21/sqrt21 = 2sqrt21/21
cot(0) = adjacent/opposite = sqrt21/2
sec(0) = hypotenuse/adjacent = 5sqrt21/21
