Question

What is the equation of the line that passes through the points (1,5) and (0,3)?

Answer 1

Answer:

y=2x+3

Step-by-step explanation:

first use the y2-y1/x2-x1 then use y=mx+b after

plug in 3 for y2 and 5 for y1

then plug in 0 for x2 and 1 for x1

$\frac{3-5}{0-1}$=$\frac{-2}{-1} =2$ and 2 is ur slope

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now use y=mx+b

i usually use the first point but u can u anyone u want

plug in 1 for x

plug in 5 for y

and plug in 2 for m

5=2(1)+b

5=2+b

subtract 2 on both sides

5-2=3

3=b and b is ur y-intercept

y=2x+3

hope this helps