Answer: i dont really know if im right but here! :L
Step-by-step explanation: Now, say G is an Abelian group, finitely generated from generator In this sense abelian groups are “more interesting” than vector spaces. and in the table below, the second last column is the identity, while the last column is cyclic of order 4, with 9g the generator
Answer:
They are not commutative, because f(g(x)) and g(f(x) are not equal.
Step-by-step explanation:
In order for the composition of the functions to be commutative, we must have ...
f(g(x)) ≡ g(f(x))
for all values of x.
Here, we have f(g(x)) = 1 and g(f(x)) = 2. f(g(x)) and g(f(x)) are not equal, so the composition of the functions is not commutative.
Answer:
{4,8,3,7,2,6,1,5,9} the sum of 4
Step-by-step explanation:
Answer:
Let's solve your equation step-by-step.
x−7=−2
Step 1: Add 7 to both sides.
x−7+7=−2+7
x=5
Step-by-step explanation:
Step 1: Add 7 to both sides.
x−7+7=−2+7
x=5
Answer:
(C)Zero
Step-by-step explanation:
Because of the zero on top of the <em>y</em> in the division anything that you multiply or divides is always zero even a negative so the answer is zero
