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Setler [38]
3 years ago
11

Hallmark would like to test the hypothesis that those celebrating Valentine's Day will spend more than an average of $125 on gif

ts. A random sample of 18 people celebrating Valentine's Day spent an average of $148.50 with a standard deviation of $34.90. Hallmark would like to set α = 0.01. Use the p-value approach to test this hypothesis.
Mathematics
1 answer:
Vaselesa [24]3 years ago
3 0

Answer:

We conclude that those celebrating Valentine's Day spend more than an average of $125 on gifts.

Step-by-step explanation:

We are given that Hallmark would like to test the hypothesis that those celebrating Valentine's Day will spend more than an average of $125 on gifts.

A random sample of 18 people celebrating Valentine's Day spent an average of $148.50 with a standard deviation of $34.90.

<u><em>Let </em></u>\mu<u><em> = average amount spent on gifts celebrating Valentine's Day</em></u>

So, Null Hypothesis, H_0 : \mu \leq $125    {means that those celebrating Valentine's Day spend less than or equal to an average of $125 on gifts}

Alternate Hypothesis, H_A : \mu > $125    {means that those celebrating Valentine's Day spend more than an average of $125 on gifts}

The test statistics that will be used here is <u>One-sample t test statistics</u> as we don't know about population standard deviation;

                               T.S.  = \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample average amount spent = $148.50

             s = sample standard deviation = $34.90

             n = sample of people = 18

So, <u>test statistics</u>  =  \frac{148.50-125}{\frac{34.90}{\sqrt{18} } }  ~ t_1_7

                                    =  2.857

The value of the sample test statistics is 2.857.

<u>Now, P-value of the test statistics is given by the following formula;</u>

          P-value = P( t_1_7 > 2.857) = <u>0.0056</u>

Because in the t table the critical value of 2.857 at 17 degree of freedom will lie between P = 1% and P = 0.5%.

Now, since P-value of test statistics is less than the level of significance as 0.01 > 0.0056, so we sufficient evidence to reject our null hypothesis.

Therefore, we conclude that those celebrating Valentine's Day spend more than an average of $125 on gifts.

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