Question

I need help with this ;-; can someone help me how to get the answer as well?

Answer 1

Answer:

(3)》》》60°

Step-by-step explanation:

Since the exterior angle of a triangle is

equal to the sum of non-adjacent interior angles, we have

<DAB=<ABC +<BCA

》180-3x =(6x-40) + (x+20)

》180-31 - 3t sx-not x+20

》180-3x - 72-20

》7x+3x= 180+20

》10x=200

》x=20°

(Being complementory angles)

<DAB+ <BAC = 180°

》180-3×20°+<BAC=180

》<BAC=60°

Answer 2

Answer: 60°

Step-by-step explanation;

Sum of angles in a ∆=180°

We sum each of the angles and equate to 180°

(6x-40) + {180- (180-3x) }+ (X+20) =180

6x+3x+x-40+20=180°

10x-20=180°

10x=180+20

10x= 200° therefore, X=20

Substitution to solve <BAC

180-3x

180-3(20)

180-60

120

Applying angle in a straight line, we have

180-120

= 60°