I need help with this ;-; can someone help me how to get the answer as well?
2 answers:
Answer:
(3)》》》60°
Step-by-step explanation:
Since the exterior angle of a triangle is
equal to the sum of non-adjacent interior angles, we have
<DAB=<ABC +<BCA
》180-3x =(6x-40) + (x+20)
》180-31 - 3t sx-not x+20
》180-3x - 72-20
》7x+3x= 180+20
》10x=200
》x=20°
(Being complementory angles)
<DAB+ <BAC = 180°
》180-3×20°+<BAC=180
》<BAC=60°
Answer: 60°
Step-by-step explanation;
Sum of angles in a ∆=180°
We sum each of the angles and equate to 180°
(6x-40) + {180- (180-3x) }+ (X+20) =180
6x+3x+x-40+20=180°
10x-20=180°
10x=180+20
10x= 200° therefore, X=20
Substitution to solve <BAC
180-3x
180-3(20)
180-60
120
Applying angle in a straight line, we have
180-120
= 60°
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