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vagabundo [1.1K]
2 years ago
15

40 POINTS PLEASE HELP!

Mathematics
1 answer:
White raven [17]2 years ago
7 0

Answer:

-1.70588235294

1. X3,    15x - 10y = 80   15x - 7y = 51

-17y = 29

2. 8 = 1/60 + a. 8 - 1/60 = 7.98333333333

  6 = 1/80 + b. 6 - 1/80 =  5.9875

                                         13.9708333333

3. I genuinely dont know sorry.

4. Pencil = $0.05. Pen = $1.05

Step-by-step explanation:

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What is the equation for a slope of -3 and y intercept of 7
Tom [10]

Answer:

Step-by-step explanation:

y=-3+7

5 0
3 years ago
Pls help me with this! (Links=report)
xxMikexx [17]

Answer:

XZ=12 in

Step-by-step explanation:

area of a rhombus is A=pq/2

where p=WY=15.5 and A=93 and q=XZ

93=15.5(XZ)/2

93(2)=15.5(XZ)

186/15.5=XZ

XZ=12 in

7 0
3 years ago
24(9) = 2x i need help with this
Degger [83]

Answer:

24×9 = 2x

216 = 2x

216÷2 = x

108 = x

x=108

4 0
3 years ago
What is X and A??? The have to equal the same thing, but one is multiplying and one is adding (picture)
Aleksandr-060686 [28]
X*a = 244  is equation (1)
x+a = 2    is equation (2)

Solve equation (2) for 'a' to get
x+a = 2
a = 2-x
Call this equation (3)

We will plug equation (3) into equation (1)
x*a = 244
x*(a) = 244
x*(2-x) = 244
Notice how the 'a' is replaced with an expression in terms of x

Let's solve for x
x*(2-x) = 244
2x-x^2 = 244
x^2-2x+244 = 0

If we use the discriminant formula, d = b^2 - 4ac, then we find that...
d = b^2 - 4ac
d = (-2)^2 - 4*1*244
d = -972
indicating that there are no real number solutions to the equation x^2-2x+244 = 0

So this means that 'x' and 'a' in those two original equations are non real numbers. If you haven't learned about complex numbers yet, then the answer is simply "no solution". At this point you would stop here. 

If you have learned about complex numbers, then the solution set is approximately 
{x = 1 + 15.588i, a = 1 - 15.588i}
which can be found through the quadratic formula

Note: it's possible that there's a typo somewhere in the problem that your teacher gave you. 

6 0
3 years ago
Which is the polynomial function of lowest degree with rational real coefficients, a leading coefficient of 3 and roots StartRoo
anastassius [24]

Answer:

a) f(x)=3x^{3}-6x^{2}-15x+30

Step-by-step explanation:

1) In this question we've been given "a", the leading coefficient. and two roots:

x_{1}=\sqrt{5}\:x_{2}=2

2) There's a theorem, called the Irrational Theorem Root that states:

If one root is in this form x'=\sqrt{a}+b  then its conjugate x''=\sqrt{a}-b. is also a root of this polynomial.

Therefore

x_3=-\sqrt{5}

3) So, applying this Theorem we can rewrite the equation, by factoring. Remembering that x is the root. Since the question wants it in this expanded form then:

f(x)=3(x-\sqrt{5})(x+\sqrt{5})(x-2)\Rightarrow 3x^{3}-6x^{2}-15x+30

4 0
2 years ago
Read 2 more answers
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