Since the 6 is bigger than 5 it means round up if it was a 4 you would round down
soo... 26
Answer:
Consider the parent logarithm function f(x) = log(x)
Now,
Let us make transformations in the function f(x) to get the function g(x)
•On streching the graph of f(x) = log(x) , vertically by a factor of 3, the graph of y = 3log(x) is obtained.
•Now, shrinking the graph of y = 3log(x) horizontally by a fctor of 2 to get the grpah of y = 3log(x/2) i.e the graph of g(x)
Hence, the function g(x) after the parent function f(x) = log(x) undergoes a vertical stretch by a factor of 3, and a horizontal shrink by a factor of 2 is
g(x) = 3 log(x/2) (Option-B).
Answer: Pay 250 per month until it’s paid off
First find out how much he makes in 8 hours (9x8=72). Then subtract 72 from 155 (155-72=83). Then divide 83 by 6 (83/6=13.8333). Since 83 is not evenly divisible by 6, and since he can't deliver .8333 of a delivery, we would round up, giving us 14). Ben would need to make 14 deliveries in 8 hours to make more than $155 :) Hope this helps you :)
Example: <span>the second step in the process for factoring the trinomial x^2-3x-40 is to:</span> <span>Well you really should find the sum of the factors of −40 (not 40) </span>
<span>But before you can do that, you need to LIST the factors of −40 (not 40) </span>
<span>−1 * 40 </span>
<span>−2 * 20 </span>
<span>−4 * 10 </span>
<span>−5 * 8 </span>
<span>−8 * 5 </span>
<span>−10 * 4 </span>
<span>−20 * 2 </span>
<span>−40 * 1 </span>
<span>NOW we find the sum of the factors of −40 </span>
<span>−1 + 40 = 39 </span>
<span>−2 + 20 = 18 </span>
<span>−4 + 10 = 6 </span>
<span>−5 + 8 = 3 </span>
<span>−8 + 5 = −3 </span>
<span>−10 + 4 = −6 </span>
<span>−20 + 2 = −18 </span>
<span>−40 + 1 = −39 </span>
<span>Then we choose the factors of −40 whose sum is −3 ---> −8 and 5 </span>
<span>x^2 − 3x − 40 = (x − 8) (x + 5) </span>
<span>So FIRST step is B, SECOND step is C, and final step is factoring. </span>
What Rita did was combine these 2 steps together, which you will learn to do as you get better at factoring.
