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3 years ago

How does sound travel and where does it travel better? please help!

1 answer:

7 0

Sound or Soundwaves travel through mediums by vibrating molecules. Sound waves mediums can often travel through gas, liquid, and solid. Compared to liquids, solids seem to travel better because the molecules that make up the matter are packed tightly.

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You connect a 100-resistor, a 800-mH inductor, and a 10.0-uF capacitor in series across a 60.0-Hz, 120-V (peak) source. The impe

steposvetlana [31]

Answer:

Impedance, Z = 107 ohms

Explanation:

It is given that,

Resistance, R = 100 ohms

Inductance, $L=800\ mH=800\times 10^{-3}\ H=0.8\ H$

Capacitance, $C=10\ \mu F=10\times 10^{-6}\ F=10^{-5}\ F$

Frequency, f = 60 Hz

Voltage, V = 120 V

The impedance of the circuit is given by :

$Z=\sqrt{R^2+(X_C-X_L)^2}$ ...........(1)

Where

$X_C$ is the capacitive reactance, $X_C=\dfrac{1}{2\pi fC}$

$X_C=\dfrac{1}{2\pi \times 60\times 10^{-5}}=265.65\ \Omega$

$X_L$ is the inductive reactance, $X_L={2\pi fL}$

$X_L={2\pi \times 60\times 0.8}=301.59\ \Omega$

So, equation (1) becomes :

$Z=\sqrt{(100)^2+(265.65-301.59)^2}$

Z = 106.26 ohms

Z = 107 ohms

So, the impedance of the circuit is 107 ohms. Hence, this is the required solution.

8 0

4 years ago

What would happen to a satellite if it’s orbit speed was reduced by half? Also how about if it doubled?

weeeeeb [17]

For finding the orbital speed of the satellite we can say that the centripetal force for the circular motion of satellite is provided by the gravitational force of earth

so here we can say

$F_g = \frac{mv^2}{r}$

$\frac{GMm}{r^2} = \frac{mv^2}{r}$

now we will have

$v = \sqrt{\frac{GM}{r}}$

now here we will say that orbital speed of the satellite is inversely depends on the orbital radius

<em>So here if orbital speed is half then as per above relation we can say that orbital distance will become four times</em>

<em>Also we can say that if orbital speed is double then orbital distance will become one fourth of initial distance.</em>

7 0

3 years ago

A mass resting on a horizontal, frictionless surface is attached to one end of a spring; the other end is fixed to a wall. It ta

Marina CMI [18]

Answer:

(a) The spring constant is 426N/m

(b) The mass is 5.65kg

Explanation:

(a) Energy stored in the spring (E) = 3.6J, extension (e) = 0.13m

E = 1/2Ke^2

3.6 = 1/2 × K × 0.13^2

K (spring constant) = 3.6×2/0.0169 = 426N/m

(b) F = Ke = 426 × 0.13 = 55.38N

Assuming the maximum acceleration (a) is 9.8m/s^2

Mass (m) = F/a = 55.38/9.8 = 5.65kg

7 0

4 years ago

A 1400-kg car is moving at a speed of 35 m/s. How much kinetic energy does the car have (in Joules)?

Gekata [30.6K]

Answer:

857.5Kjoules

Explanation:

Using K. E=1/2 Mv^2

=1/2x1400x35x35

=857500joules

=857.5KJ

3 0

3 years ago

An incompressible fluid is flowing through a horizontal pipe with a constriction. The velocity of the fluid in the wide section

lapo4ka [179]

The Bermoulli's equation allows us to find the pressure in the narrow part of the pipe through which water circulates is:

P = 500 Pa

Bernoulli's equation is the work-energy relationship for fluids that are liquids and gases.

$P_1 + \frac{1}{2} \rho v_1^2 + \rho g y_1 = P2 + \frac{1}{2} \rho v_2^2 + \rho g y_2$

Where the subscripts 1 and 2 represent points of interest, P is the pressure, ρ the density of the fluid, v the velocity and y the height.

They indicate that the pipe is horizontal, that the pressure in the wide part P₁ = 200 kPa and the velocity is v₁ = 5 m / s and in the narrow part v₂=8.00 m/s, see attached.

Since the pipe is horizontal y₁ = y₂

P₁ + ½ ρ v₁² = P₂ + ½ ρ v₂²

P₂ = P₁ + ½ ρ (v₁² - v₂²)

Let's calculate

P₂ = 200 10² + ½ ρ (5² - 8²)

P₂ = 2 10⁴ - 19.5 ρ

For a specific calculation the value of the density of the fluid is needed, suppose that the fluid is water ρ = 1000 kg / m³

P₂ = 2 10² - 19.5 1000

P₂ = 500 Pa

In conclusion using the Bermoulli equation we can find the pressure in the narrow part of the pipe through which water circulates is:

P = 500 Pa

Learn more here: brainly.com/question/9506577

3 0

3 years ago