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Yuki888 [10]
3 years ago
14

When a sound wave travels through air, how is this air affected by its passage

Physics
1 answer:
grandymaker [24]3 years ago
6 0
Sound is a mechanical wave <span>that results from the back and forth vibration of the particles of the medium through which the sound wave is moving. If a sound wave is moving from left to right through air, then particles of air will be displaced both rightward and leftward as the energy of the sound wave passes through it. The motion of the particles is parallel (and anti-parallel) to the direction of the energy transport. This is what characterizes sound waves in air as longitudinal waves.</span><span>
</span>
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1.A boy runs at a speed of 3.3 m/s straight off the end of a diving board that is 3 meters above the water
Whitepunk [10]

Answer:45

Explanation:

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3 years ago
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We observe a glowing cloud of gas in space with a spectroscope. We note that many of the familiar lines of hydrogen that we know
astra-53 [7]
The answer is A because for it to shift to a blue violet it has to increase in temperature
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3 years ago
A 523.2-W space heater is designed for operation in Germany, where household electrical outlets supply 230 V (rms) service. What
photoshop1234 [79]

Answer:

power = 142.4 W

Explanation:

power of heater in Germany (P₁) = 523.2 W

power of heater in America (P₂) = ?

outlet voltage in Germany (V₁) = 230 V

outlet voltage in America (V₂) = 120 V

  • While in Germany, power = \frac{V₁^{2}}{R}

         523.2 = \frac{230^{2}}{R}

         R = 101.1

  • While in America, also power = \frac{V₂^{2}}{R}

         using the value of R gotten above

         power = \frac{120^{2}}{101.1}

        power = 142.4 W

6 0
3 years ago
A solid sphere of mass 2.50 kg and radius 0.120 m is at rest at the top of a ramp inclined 15.0°. It rolls to the bottom without
Lubov Fominskaja [6]

Answer:

KE= 30 J

Explanation:

Given that

m= 2.5 kg

r= 0.12 m

θ = 15°

h= 1.2 m

As we know that solid sphere rolls without slipping.It means that

v= ω r

v=Linear velocity

ω=Angular speed

r=radius

The total kinetic energy KE

KE=\dfrac{1}{2}mv^2+\dfrac{1}{2}I\omega^2

Moment of inertia of solid sphere I

I=\dfrac{2}{5}mr^2

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Energy at top = Energy at bottom

The potential energy at top = m g h

Potential energy at bottom = 0

Kinetic energy at top = 0

Kinetic energy at bottom = KE

m g h + 0 = 0 + KE

KE= 2.5 x 10 x 1.2                 ( take g =10 m/s²)

KE= 30 J

7 0
3 years ago
For each description, choose the fault it describes. Fault types may be used more than once.
MArishka [77]

Answer;

  • Rock layers are placed under compressional stress:  Reverse Fault
  • Rock layers are placed under tensional stress:  Normal Fault
  • Hanging wall has dropped relative to footwall:  Normal Fault
  • Hanging wall has risen relative to footwall: Reverse faults

Explanation;

A normal fault occurs because two tectonic plates are pulling apart from each other, causing tensional stress. The stress allows gravity to pull the hanging wall downward along the footwall, making a cliff-like formation called a scarp. Thus, if you see the hanging wall has dropped relative to the footwall, it is a normal fault. Normal faults occur at divergent boundaries.

A reverse fault happens at convergent boundaries, where two plates colliding produce compressional stress. As the two plates come together, the pressure causes the hanging wall to move upward along the footwall. These breaks are reverse faults because the hanging wall moves in an opposite, or reverse, direction when compared to a normal fault.

A strike-slip fault occurs when tectonic forces cause rock layers to break apart and move in opposite, parallel directions, causing shear stress. The rock layers in a strike-slip fault move sideways past one another.


3 0
3 years ago
Read 2 more answers
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