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Arlecino [84]
3 years ago
11

You need at least $535 to go on a trip to California. You have already save $200. You decide to save an additional $25 per week.

Which inequality shows the number of weeks, w, you need to save to be able to go on the trip?
Mathematics
2 answers:
FrozenT [24]3 years ago
4 0

Answer:

200+25w

Step-by-step explanation:

200=starting amount

25=every week gaining

w=weeks

Answer= 14.5 weeks

Hope it helps!

Marat540 [252]3 years ago
3 0

Answer:

25w+200\geq 535

Step-by-step explanation:

Let's call w the number of weeks.

Notice that the problem says "at least $535" this means the minimum is $535 or more, so we have to use the symbol \geq.

Also, you are gonna save $25 per week, which means this is the ratio of change, the coefficient of the variable.

Additionally, you already have $200, so that's the constant of the expression.

Therefore, the expression that models this situation is

25w+200\geq 535

We can solve for w to find the minimum number of weeks you need to save

25w+200\geq 535\\25w \geq 535-200\\w\geq \frac{335}{25}\\ w\geq 13.4

So, you need to save for at least 14 weeks.

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If a=8 and b=5 and x=4 and y=6m -2 what is the value of m ?
Serga [27]

Answer:

m = 2

Step-by-step explanation:

Given:

x = 4

y = 6m - 2

a = 8

b = 5

Required:

Value of m

SOLUTION:

x and y are segments of a chord divided when it intersects another chord that also has segments a and b.

According to the Intersecting chords theorem, a*b = x*y

Thus:

8*5 = 4*(6m - 2)

Solve for m

40 = 24m - 8

40 + 8 = 24m - 8 + 8

48 = 24m

\frac{48}{24} = \frac{24m}{24}

2 = m

The value of m = 2

3 0
3 years ago
The numbers of teams remaining in each round of a single-elimination tennis tournament represent a geometric sequence where an i
Anit [1.1K]

Answer:

a_n = 128\bigg(\dfrac{1}{2}\bigg)^{n-1}

Step-by-step explanation:

We are given the following in the question:

The numbers of teams remaining in each round follows a geometric sequence.

Let a be the first the of the geometric sequence and r be the common ration.

The n^{th} term of geometric sequence is given by:

a_n = ar^{n-1}

a_4 = 16 = ar^3\\a_6 = 4 = ar^5

Dividing the two equations, we get,

\dfrac{16}{4} = \dfrac{ar^3}{ar^5}\\\\4}=\dfrac{1}{r^2}\\\\\Rightarrow r^2 = \dfrac{1}{4}\\\Rightarrow r = \dfrac{1}{2}

the first term can be calculated as:

16=a(\dfrac{1}{2})^3\\\\a = 16\times 6\\a = 128

Thus, the required geometric sequence is

a_n = 128\bigg(\dfrac{1}{2}\bigg)^{n-1}

4 0
3 years ago
A tv that normally cost $800
sukhopar [10]

what is the question it might be an Sony-75"

6 0
2 years ago
If the ceos salary of 1,000,000 is taken out of the list what I would happen to the mean and median 25,25,25,35,35,45,45,55,55
Mama L [17]

Answer:

Both the mean and median decrease.

Step-by-step explanation:

Median (without 1,000,000):

<em>25, 25, 25, 35</em>, 35,<em> 45, 45, 55, 55</em>

= 35

Median (with 1,000,000):

<em>25, 25, 25, 35</em>, 35, 45, <em>45, 55, 55, 1,000,000</em>

= average of 35 and 45

= 40

As you can see, without the outlier, the value of the median decreases.

Mean (without 1,000,000):

= (25 + 25 + 25 + 35 + 35 + 45 + 45 + 55 + 55) / 9

= 38.3

Mean (with 1,000,000):

= (25 + 25 + 25 + 35 + 35 + 45 + 45 + 55 + 55 + 1,000,000) / 10

= 100,0034.5

As you can see, without the outlier, the value of the mean dramatically decreases.

6 0
2 years ago
15d^3+30d^2+30d/3d3 what is the answer if you divide the following
lawyer [7]
When you separate them
\frac{15d^{3} }{ {3d}^{3} }  +  \frac{30d^{2} }{ {3d}^{3} }  +  \frac{30d }{ {3d}^{3} }   = x
Solve them separately:
5 +  \frac{10}{d}  +  \frac{10}{ {d}^{2} }  = x
Remove the denominators:
5 + 10 {d}^{ - 1}  + 10 {d}^{ - 2}  = x
Find GCF (Greatest Common Factor):
5(1 + 2 {d}^{ - 1}  + 2 {d}^{ - 2} ) = x
5 0
3 years ago
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