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Nesterboy [21]
3 years ago
13

Evaluate: |18| A:1/18 B:-1/-18 C:-18 D18

Mathematics
1 answer:
masya89 [10]3 years ago
4 0
Answer will be D. Absolute value can never be negative.
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Solve the absolute value equation or indicate that the equation has no solution. |x-5|=4
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Step-by-step explanation:

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2 years ago
Simplify expression X^2+x-2/x^3-x^2+2x-2
professor190 [17]

Answer:


=\frac {x+2}{x^2+2} is the simplest form of given expression.


Step-by-step explanation:

The given question is \frac{x^2+x-2}{x^3-x^2+2x-2}


To solve the problem we have to group or split middle term and then factorise


\frac{x^2+(2x-x)-2}{(x^3-x^2)+(2x-2)}


Taking x^2 common from first two terms of denominator and 2 from next two terms


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Now,taking x common from first two terms of numerator and -1 from next two terms and in denominator taking(x-1) common from both terms


= \frac{ x(x+2)-1(x+2)}{(x-1)(x^2+2)}



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Now cancel out x-1 from both numerator and denominator we get


=\frac {x+2}{x^2+2} is the required simplest form.



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You are given two equations, solve for one variable in one of the equations. Say you solved for x in the second equation. Then, plug in that value of x in the x of the first equation. Solve this (first) equation for y (as it should become apparent) and you'll get a number value. Plug in this numerical value of y into the y of the second equation. Solve for x in the second equation. And there you have it: (x, y)
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4fg^{2}

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