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3 years ago

Help me by showing me the step

Mathematics

1 answer:

MatroZZZ [7]3 years ago

8 0

Answer:

1. 15

Step-by-step explanation:

I'll help you out with question #1 and follow these steps to help you with solving the rest of the problems.

1. $\frac{6-x}{3} = y$ and we know that $y=-3$ .

We can substitute $y=-3$ to the first equation.

$\frac{6-x}{3} = -3$

Multiply both sides by 3 to get rid of the fraction.

$6-x = -9$

Now you can solve for $x$ , for which the value is 15.

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Explain how you can use place-value patterns to describe how 50 and 5,000 compare.

Kobotan [32]

<span>=> 50 and 5000
Place value are very useful to compare given numbers. Place value gives ideas on how big the number is and helps you compare easily what is greater and lesser.

Let’s use the given number:
50 => 50 has 2 digit whole number, which means it has a place value of tens
=> 5 tens and 0 ones.

5000 => is a 4 digit whole number, which means it as a place value of 5000
=> 5 thousands 0 hundreds, 0 tens and 0 ones.

5000 is 100 times greater than 50.
=> 50 x 100 = 5000</span>

6 0

4 years ago

In a study, researchers wanted to measure the effect of alcohol on the hippocampal region, the portion of the brain responsibl

schepotkina [342]

Answer:

$t=\frac{8.19-9.02}{\frac{0.8}{\sqrt{17}}}=-4.28$

The degrees of freedom are given by

$df=n-1=17-1=16$

The p value would be given by this probability:

$p_v =P(t_{(16)}$

Since the p value is lower than the significance level provided of 0.01 we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly lower than 9.02 cm^3

Step-by-step explanation:

Information given

$\bar X=8.19 cm^3$ represent the sample mean

$s=0.8 cm^3$ represent the sample deviation

$n=17$ sample size

$\mu_o =9.02$ represent the value to verify

$\alpha=0.01$ represent the significance level for the hypothesis test.

t would represent the statistic

$p_v$ represent the p value

System of hypothesis to check

We want to check if the true mean is less than the normal value of 9.02 cm^3, the system of hypothesis would be:

Null hypothesis: $\mu \geq 9.02$

Alternative hypothesis: $\mu < 9.02$

The statistic for this case is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing the info given we got:

$t=\frac{8.19-9.02}{\frac{0.8}{\sqrt{17}}}=-4.28$

The degrees of freedom are given by

$df=n-1=17-1=16$

The p value would be given by this probability:

$p_v =P(t_{(16)}$

6 0

3 years ago

2-33+(-4)+5-(-6)-70=

VikaD [51]

2-33+(-4)+5-(-6)-70=

2-33-4+5+6-70=
-35+5+6-70=
-30+6-70=
-24-70=
-94

Answer=-94

5 0

3 years ago

Can someone help me with 21

victus00 [196]

1. 10.4
2. 9.3
3. 10.3

6 0

3 years ago

Please help thank you.

alina1380 [7]

Hello!

To solve this we use the equation sin60 = (s/2) / (d/2)

s is a side of the triangle
d is the diameter

sin60 = s/d

$\sqrt{3/4} =s/d$

$d=s/ \sqrt{3/4}$

$d = s \sqrt{4/3}$

$d = 2s/ \sqrt{3}$

put 6 in for s

$d=12/ \sqrt{3}$

$d = \sqrt{48}$

d = 6.9

The answer is C) 6.9

Hope this helps!

5 0

4 years ago