Answer:
The system of equations has one solution. The two equations are intersecting lines.
Step-by-step explanation:
if you want to use the substitution method, you would have to plug in y for 12x+2 in the second equation.
2(12x+2)=x+4
next, you have to distribute
24x+4=x+4
subtract 24x from each side
4=-23x+4
subtract 4 from each side
0=23x
divide each side by 23
x=0
now, plug in 0 to one equation.
y=12(0)+2
y=2
the lines intersect at one point, (0,2)
8x-4 and 4(2x-1)
4(2x-1) the four needs to be distributed in the parentheses.
4*2x=8x
4*(-1)=(-4)
8x-4=8x-4
If these triangles are congruent, then side RS is congruent to side TV and that means that y = 4 - x. If y = 4-x, we can sub that into the next equation where side RV = side ST and 1 = 4x - y. If y = 4-x, we sub in accordingly to get 1 =4x - (4 - x). That simplifies to 1 = 4x - 4 + x which is, combining like terms, 5 = 5x. That means that x = 1. If x = 1, and y = 4 - x, then y = 4 - 1 and y = 3. There you go!
Subtract 2 from both sides
3x+2-2=5-2
3x=3
Divide both sides by 3
3x/3= 3/3
The answer is ×=1