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natima [27]
2 years ago
6

Does subtraction exhibit the property of closure over the set of real numbers.

Mathematics
1 answer:
victus00 [196]2 years ago
4 0
Yea it dose but it still doesn't work out well
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Which of the following values of x makes this equation true? (-4x – 3) - (7x - 3) = 22​
Katena32 [7]

Answer:

Step-by-step explanation:

Here you go mate

Step 1

(-4x-3)-(7x-3) =22​  Equation

Step 2

(-4x-3)-(7x-3) =22​  Simplify

-11x=22

Step 3

-11x=22  Divide

Answer

x=-2

5 0
3 years ago
Solve the linear equation:<br><br> x-y=7<br><br> 0.5x+y=5
evablogger [386]

Add the equations.

x-y%2B0.5x%2By=7%2B5

1.5x=12

 

highlight%28x=8%29

Now use either equation to solve for y.

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4 0
3 years ago
a student was given the equation x^2+6x-13=0 the next step in the students process was x^2+6x+c=13+c state the value of c that c
Ratling [72]
This is the process of completing the square. 
Keep this equation in mind: ax^2+bx+c
Basically, to make this a perfect square trinomial, you take half of b and square that value. This will make it so you can compress the left side of the equation into (x+b)^2 \ or \ (x-b)^2 depending on the sign in the middle of the original equation.
4 0
3 years ago
A sample with which of these variances has a standard deviation that is greater than the variance
KIM [24]
Hello.

The answer is 

C.0.5 

the standard is .50 and all of the other options are larger so it would be c.

Have a nice day
8 0
3 years ago
Read 2 more answers
A circular swimming pool has a radius of 28 ft. There is a path all the way around the pool that is 4 ft wide. A fence is going
AleksAgata [21]

Answer:

200.96 feet

Step-by-step explanation:

We have a pool with a radius of 28 feet.

They also tell us that there is a path around the pool and its width is 4 feet.

Thus:

The radius of the outer edge of the pool path would be equal to the radius of the pool plus the width of the path.

= (28 + 4) feet

= 32 feet

To find the length of the fence, we need to find the circumference of the outside of the pool path. The radius is then equal to 32 feet.

The circumference of the outer edge of the pool path would be equal to the perimeter.

p = 2 * pi * r

replacing

p = 2 * 3.14 * 32

p = 200.96 feet

therefore 200.96 feet are needed

4 0
3 years ago
Read 2 more answers
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