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3 years ago

Can somebody help me with this problem :)

Mathematics

1 answer:

galina1969 [7]3 years ago

7 0

Answer: I am really sorry if this answer is not what you were expecting. Don’t get mad if I get it wrong but I’m just gonna go out on a limb here and say that the answer is 4.5 or 5.3

Step-by-step explanation:

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What is the slope of the line that passes through the points (3,1) and (-2,5)

evablogger [386]

Answer:

D.) -4/5

Step-by-step explanation:

Ok, so we need to calculate the change in y over the channge in x, rise over run.

(3-(-2)=5 1-5=-4) -4/5

6 0

3 years ago

Read 2 more answers

Pluto's distance P(t)P(t)P, left parenthesis, t, right parenthesis (in billions of kilometers) from the sun as a function of tim

Xelga [282]

Answer: P(t) = 1.25.sin( $\frac{\pi}{3}$ .t) + 5.65

Step-by-step explanation: A motion repeating itself in a fixed time period is a periodic motion and can be modeled by the functions:

y = A.sin(B.t - C) + D or y = Acos(B.t - C) + D

where:

A is amplitude A=|A|

B is related to the period by: T = $\frac{2.\pi}{B}$

C is the phase shift or horizontal shift: $\frac{C}{B}$

D is the vertical shift

In this question, the motion of Pluto is modeled by a sine function and doesn't have phase shift, C = 0.

Amplitude:

a = $\frac{largest - smallest}{2}$

At t=0, Pluto is the farthest from the sun, a distance 6.9 billions km away. At t=66, it is closest to the star, P(66) = 4.4 billions km. Then:

a = $\frac{6.9-4.4}{2}$

a = 1.25

b

A time period for Pluto is T=66 years:

66 = $\frac{2.\pi}{b}$

b = $\frac{\pi}{33}$

Vertical Shift

It can be calculated as:

d = $\frac{largest+smallest}{2}$

d = $\frac{6.9+4.4}{2}$

d = 5.65

Knowing a, b and d, substitute in the equivalent positions and find P(t).

P(t) = a.sin(b.t) + d

P(t) = 1.25.sin( $\frac{\pi}{3}$ .t) + 5.65

The Pluto's distance from the sun as a function of time is

P(t) = 1.25.sin( $\frac{\pi}{3}$ .t) + 5.65

8 0

3 years ago

What is the value of 6 (2b-4) When b=5

e-lub [12.9K]

Answer:

Step-by-step explanation:

Replace the 2b with 10 and then do the parenthesis, so 10-4=6

now multiply it with the 6 outside the parenthesis and you get 36

7 0

3 years ago

Read 2 more answers

Plz help me with these math questions

Akimi4 [234]

For b on the first paper you will start with the distribution property and multiply both x and 2 by 3 because they are in the ()
now you have 3x+ 6=x-18
from here you can subtract x from both sides
2x+6=-18
next subtract 6 from both sides
2x=-24
divide both sides by 2...
x=-12
hope this helped

8 0

3 years ago

The vectors u1 = (1, 2, −1), u2 = (2, 6, 6), u3 = (−1, −3, −3), u4 = (0, 2, 8), and u5 = (3, 7, −3) generate R 3 . Find a subset

sukhopar [10]

Answer:

(u3,u4,u5)

Step-by-step explanation:

For finding a subset x of the set {u1, u2, u3, u4, u5} that is a basis for R3 we need to prove that x is linear independent and it's a generator of R3.

(0,0,0)=a(1,2,-1)+b(2,6,6)+c(-1,-3,-3)

(0,0,0)=(a+2b-c,2a+6b-3c,-a+6b-3c)

the system is not linear independent so (u1,u2,u3) can not be a basis of R3.

If we do the same procedure with u3 = (−1, −3, −3), u4 = (0, 2, 8), and u5 = (3, 7, −3)

(0,0,0)=a(-1,-3,-3)+b(0,2,8)+c(3,7,-3)

(0,0,0)=(-a+0b+3c,-3a+2b+7c,-3a+8b-3c)

If we solve the system of equations we have that: a=0, b=0, c=0. So the subset is linear independent.

Then we need to prove that it's a generator of R3

(x,y,z)=a(-1,-3,-3)+b(0,2,8)+c(3,7,-3)

(x,y,z)=(-a+0b+3c,-3a+2b+7c,-3a+8b-3c)

If we solve the system of equations we have that: x=-a+3c, y=-3a+2b+7c, z=-3a+8b-3c. So the subset is linear combination into R3 so it generates R3.

4 0

3 years ago