Find slope of a line passing through points (-8 , -3) and (-3 , 4).
1 answer:
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Answer:
y = csc(x - 3/4)
Step-by-step explanation:
I forgot how to answer questions like these. I went ahead and tried re-learning this to answer this.
So, the first step is to recognize that this graph can only be the reciprocal function of sin or cosine. I will think of sine.
y = sin(x)
Look at where the x-coordinate of the sin is. (-3/4PI). This is going to be the c value. { y = asin(x-c) }
y = sin(x - 3/4)
Now, what is the a value? or amplitude? Well, it's just 1.. and the simplest explanation is just to look at my picture.
Now, if we were to graph this, we would end up with the correct x and y values, but the shape is wrong, and the easiest way to fix this is to just take the recpriocal of the sine function.
y = csc(x - 3/4)
Thank you for this question, I re-learned something I forgot back in pre-calc haha.
