Simplify cosθ + cosθtan2θ. 1 cscθ secθ sin2θ

HHHHHEEEEELLLLLPPPPP!!!!!!!!!!!!!!!!!!!!!!!

Ira Lisetskai [31]

x/y where x and y are integers and y≠0 (rational)

2x where x is irrational (irrational)

(√2)/y where y is irrational (cannot be determined)

6 0

4 years ago

Help me please-math question

vlada-n [284]

Answer: Median = 50

Step by Step Explanation:

1. Sort the values from smallest to largest (Ascending order) - This step is already done for you in this data set.

2. Find the middle most number. If you're left with two numbers in the middle, find the average of those two numbers - Since this data set is pretty small, you can probably notice that the middle most number is 50.

I hope this helps! :D

8 0

3 years ago

Read 2 more answers

Solve the equation using the quadratic formula. X^2-9x+3=0

Nesterboy [21]

Answer:

The answer is x= $\frac{9+\sqrt{69}}{2}$ , x= $\frac{9-\sqrt{69}}{2}$

Step-by-step explanation:

x^2=a

-9x=b

3=c

Plug into formula.

Equation: $\frac{9+-\sqrt{(-9)^2-4(1)(3)}}{2}$

Simplify the equation.

Equation: $\frac{9+-\sqrt{81-12}}{2}$

Subtract 81 and 12.

Equation: $\frac{9+-\sqrt{69}}{2}$

Spit into two equations

Equation 1: $\frac{9+\sqrt{69}}{2}$

Equation 2: $\frac{9-\sqrt{69}}{2}$

Hope this helps!

8 0

3 years ago

Find the x-coordinates of any relative extrema and inflection point(s) for the function f(x)= 6x^1/3 + 3x^4/3. You must justify

irina [24]

Answer:

x-coordinates of relative extrema = $\frac{-1}{2}$

x-coordinates of the inflexion points are 0, 1

Step-by-step explanation:

$f(x)=6x^{\frac{1}{3}}+3x^{\frac{4}{3}}$

Differentiate with respect to x

$f'(x)=6\left ( \frac{1}{3} \right )x^{\frac{-2}{3}}+3\left ( \frac{4}{3} \right )x^{\frac{1}{3}}=\frac{2}{x^{\frac{2}{3}}}+4x^{\frac{1}{3}}$

$f'(x)=0\Rightarrow \frac{2}{x^{\frac{2}{3}}}+4x^{\frac{1}{3}}=0\Rightarrow x=\frac{-1}{2}$

Differentiate f'(x) with respect to x

$f''(x)=2\left ( \frac{-2}{3} \right )x^{\frac{-5}{3}}+\frac{4}{3}x^{\frac{-2}{3}}=\frac{-4x^{\frac{2}{3}}+4x^{\frac{5}{3}}}{3x^{\frac{2}{3}}x^{\frac{5}{3}}}\\f''(x)=0\Rightarrow \frac{-4x^{\frac{2}{3}}+4x^{\frac{5}{3}}}{3x^{\frac{2}{3}}x^{\frac{5}{3}}}=0\Rightarrow x=1$