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alexandr1967 [171]

2 years ago

9

I do not understand this please help me

1 answer:

muminat2 years ago

5 0

Answer: Plane AEF

Step-by-step explanation: Parallel means equal or same as. If you follow the letters BCD you can see that it sorta makes a triangle shape. So if you follow the answer choices you could see that AEF is the only one that does what BCD does if that makes sense :)

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Help fast pls. Need it due fast

Gelneren [198K]

3x+8=5x-1
3x-5x=-1-8
-2x=-9
x=4,5

AM=3x4,5+8=21,5
MB=5x4,5-1=21,5
AB=AM+MB
AB=21,5+21,5=43

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2 years ago

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Regina’s teacher recently gave her a homework assignment on solving equations. Since she has been thinking about saving for a ne

creativ13 [48]

Answer:

sdcsdcsdcs

Step-by-step explanation:

sdcdsc

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2 years ago

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See if you are cool enough to do the whole paper. i will give brainliest if correct

Deffense [45]

Answer:

1. (-9.5,0)

2. (2,0)

3.(-1,0)

4.(6.5,0)

5.(-1,4)

6. (0,-4)

7.(4,1)

8. (-8,18)

3 0

3 years ago

Find the area of the polygon

Natali [406]

Answer:

20 cm^2

Step-by-step explanation:

Sectioned it off and multiplied the length by the width

5 0

3 years ago

A decorative window is made up of a rectangle with semicircles at either end. The ratio of AD to AB is 3:2 and AB is 30 inches.

scZoUnD [109]

Answer: The required ratio will be

$84:1034$

Step-by-step explanation:

Since we have given that

Ratio of AD to AB is 3:2

Length of AB = 30 inches

So, it becomes

$2x=30\\\\x=\frac{30}{2}=15\ inches$

So, Length of AD becomes

$3x=3\times 15=45\ inches$

Now, at either end , there is a semicircle.

Radius of semicircle along AB is given by

$\frac{30}{2}=15\ inches$

So, Area of semicircle along AB and CD is given by

$2\times \frac{\pi r^2}{2}\\\\=\frac{22}{7}\times 15\times 15\\\\=\frac{4950}{7}\ in^2$

Radius of semicircle along AD is given by

$\frac{45}{2}=22.5\ inches$

Area of semicircle along AD and BC is given by

$2\times \frac{1}{2}\pi r^2\\\\=\frac{22}{7}\times \frac{45}{2}\times \frac{45}{2}\\\\=\frac{445500}{28}\ in^2$

And the combined area of the semicircles is given by

$\frac{4950}{7}+\frac{445500}{28}\\\\=\frac{465300}{28}\ in^2$

Area of rectangle is given by

$Length\times width\\\\=AD\times AB\\\\=45\times 30\\\\=1350\ in^2$

Hence, Ratio of the area of the rectangle to the combined area of the semicircles is given by

$1350:\frac{465300}{28}\\\\=1350\times 28:465300\\\\=37800:465300\\\\=84:1034$

Hence, the required ratio will be

$84:1034$

8 0

3 years ago