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slavikrds [6]
3 years ago
13

1. 0 = 2x2 + 17x + 30

Mathematics
2 answers:
Anna11 [10]3 years ago
8 0

Answer:

Simplify the equation and find the value of x

Step-by-step explanation:

1 = 34 + 17x \\  - 17x =  - 1 + 34 \\ 17x =  - 33 \\  \\ x =  -  \frac{33}{17}

horrorfan [7]3 years ago
5 0

Answer:

X=(2.5, 6)

Step-by-step explanation:

Simplifying

2x2 + -17x = -30 , Reorder the terms:  -17x + 2x2 = -30

Solving

-17x + 2x2 = -30

Solving for variable 'x'.

Reorder the terms:

30 + -17x + 2x2 = -30 + 30

Combine like terms: -30 + 30 = 0

30 + -17x + 2x2 = 0

Factor a trinomial.

(5 + -2x)(6 + -1x) = 0

Subproblem 1

Set the factor '(5 + -2x)' equal to zero and attempt to solve:

Simplifying

5 + -2x = 0

Solving

5 + -2x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-5' to each side of the equation.

5 + -5 + -2x = 0 + -5

Combine like terms: 5 + -5 = 0

0 + -2x = 0 + -5

-2x = 0 + -5

Combine like terms: 0 + -5 = -5

-2x = -5

Divide each side by '-2'.

x = 2.5

Simplifying

x = 2.5

Subproblem 2

Set the factor '(6 + -1x)' equal to zero and attempt to solve:

Simplifying

6 + -1x = 0

Solving

6 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-6' to each side of the equation.

6 + -6 + -1x = 0 + -6

Combine like terms: 6 + -6 = 0

0 + -1x = 0 + -6

-1x = 0 + -6

Combine like terms: 0 + -6 = -6

-1x = -6

Divide each side by '-1'.

x = 6

Simplifying

x = 6

Solution

x = {2.5, 6}

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Help please!!!!!!!!!
In-s [12.5K]

ANSWER

24


EXPLANATION

For a matrix A of order n×n, the cofactor C_{ij} of element a_{ij} is defined to be


   C_{ij} = (-1)^{i+j} M_{ij}


M_{ij} is the minor of element a_{ij} equal to the determinant of the matrix we get by taking matrix A and deleting row i and column j.


Here, we have


   C_{11} = (-1)^{1+1} M_{11} = M_{11}


M₁₁ is the determinant of the matrix that is matrix A with row 1 and column 1 removed. The bold entries are the row and the column we delete.


   \begin{aligned} A=\begin{bmatrix} \bf 1 & \bf -6 & \bf -4\\ \bf 7 & 0 & -3 \\ \bf -9 & 8 & -8 \end{bmatrix} \implies M_{11} &= \text{det}\left(\begin{bmatrix} 0&-3 \\ 8&-8 \end{bmatrix} \right)  \end{aligned}


Since the determinant of a 2×2 matrix is


   \det\left(  \begin{bmatrix} a & b \\ c& d  \end{bmatrix} \right) = ad-bc


it follows that


   \begin{aligned} A=\begin{bmatrix} \bf 1 & \bf -6 & \bf -4\\ \bf 7 & 0 & -3 \\ \bf -9 & 8 & -8 \end{bmatrix} \implies M_{11} &= \text{det}\left(\begin{bmatrix} 0&-3 \\ 8&-8 \end{bmatrix} \right) \\ &= (0)(-8) - (-3)(8) \\ &= -(-24) \\ &= 24 \end{aligned}


so C_{11} = M_{11} = 24

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3 years ago
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WITCHER [35]

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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