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lakkis [162]
3 years ago
6

To the model estimated in table 8.1, add the interaction term, e401k · inc. estimate the equation by ols and obtain the usual an

d robust standard errors. what do you conclude about the statistical significance of the interaction term?
Mathematics
1 answer:
taurus [48]3 years ago
3 0
Please Send Lions, Monkeys, Cats And Zebras Into Lovely Hot Countries
Signed General Penguin
P - potassium
S - sodium
L - lithium
M - magnesium
C - calcium
A - aluminium
Z - zinc
I - iron
L - lead
H - hydrogen
C - copper
S - silver
G - gold
<span>P - platinum</span>
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When doing a throw in how many of your feet should be touching the ground.
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How is the interest rate on a payday loan calculated?
snow_lady [41]

Answer:

b. total fees divided by loan amount

Step-by-step explanation:

The interest rate on a payday loan is usually calculated by dividing the total fees accrued in the loan repayment calculation by the exact loan amount.

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You operate a gaming Web site, www.mudbeast.net, where users must pay a small fee to log on. When you charged $3 the demand was
Doss [256]

Answer:

A) The linear relation between price and demand is:

d=-550x+2750

The revenue R is:

R=-550x^2+2750x

B) The profit functionP is:

P=-550x^2+2750x-30

C) The largest monthly profit is obtained with a log-on fee of $2.5 per month. This corresponds to a profit of $3407.5.

Step-by-step explanation:

We have a site where the number of log-ons depends on our monthly fee. A linear relation is established between the price (log-on fee) and the number of log-ons.

We have two points for this linear relationship:

  • At price x=3, the demand is d=1100.
  • At price x=2.5, the demand is d=1375.

We will model the relation:

d=mx+b

We can calculate the slope m as:

m=\dfrac{\Delta d}{\Delta x}=\dfrac{d_2-d_1}{x_2-x_1}=\dfrac{1375-1100}{2.5-3}\\\\\\m=\dfrac{275}{-0.5}=-550

Then, replacing one point in the linear equation, we can calculate the intercept b:

d_1=mx_1+b\\\\1100=(-550)\cdot 3+b\\\\1100=-1650+b\\\\b=1100+1650=2750

Then, the linear relation between demand and price is:

d=-550x+2750

The revenue R can be expressed as the multiplication of the price and the demand:

R=x\cdot d=x(-550x+2750)=-550x^2+2750x

If we have a fixed cost of $30 per month, the profit P is:

P=R-FC=-550x^2+2750x-30

We can maximize the profit by deriving the profit function and making it equal to zero.

\dfrac{dP}{dx}=0\\\\\\\dfrac{dP}{dx}=-550(2x)+2750(1)=0\\\\\\-1100x+2750=0\\\\x=\dfrac{2750}{1100}=2.5

This corresponds to a profit of:

P(2.5)=-550(2.5)^2+2750(2.5)-30\\\\P(2.5)=-550\cdot 6.25+6875-30\\\\P(2.5)=-3437.5+6875-30\\\\P(2.5)=3407.5

5 0
3 years ago
Differentiation y=x^-5 ?
OLga [1]

Answer:

the differentiation d/dx will be ..... -5x^-6

5 0
3 years ago
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