10(4^2-(9)
Since 16-9 is 7
And 10 times 7 is 70
A dilation would produce<span> a </span>similar figure. Therefore, the sequence of transformations that will produce a similar but not congruent figures would be the first and the third option. Figure TUVWX is dilated by a scale factor of 6 and then rotated 90° counterclockwise around the origin; and f<span>igure TUVWX is reflected across the x-axis and dilated by a scale factor of 7. Hope this answers your question.</span>
3x^(2)+4x-3x-5-2=0
3x^(2)+x-7=0
Discriminat= b^(2)-4ac= 1^(2)-4(3)(-7)= 1-12(-7)=1+84=85
The discrimination is bigger than 0 (delta>0) therefore there are 2 real solutions
Y=7x+9 here’s your answer
