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Svet_ta [14]
3 years ago
6

Find the area of a triangle with a base length of 3 units and a height of 4 units. (1 point)

Mathematics
2 answers:
atroni [7]3 years ago
6 0
Answer is B 6
I am sure thet its correct
8090 [49]3 years ago
5 0

Answer:

B

Step-by-step explanation:

  1. 1/2×bh
  2. 1/2×3×4
  3. 6square unit
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The price of a technology stock was $9.66 yesterday. Today, the price fell to $9.55. Find the percentage decrease.
Fittoniya [83]
So the decrees would be 0.11 because if you add 9.55 with 0.11 you would get 9.66 then to make sure it’s right you subtract 9.66 by 0.11 and you would get 9.55. So the answer is 0.11
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3 years ago
Solve the question 12 = 24x + 12.
Kisachek [45]

Answer:

The answer is 0.

Step-by-step explanation:

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3 years ago
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A supervisor finds the mean number of miles that the employees in a department live from work. he finds x overbar = 29 and s = 3
V125BC [204]

A supervisor finds the mean number of miles that the employees in a department live from work is 24. Then the correct option is B.

<h3>What is a z-score?</h3>

The z-score is a numerical measurement used in statistics of the value's relationship to the mean of a group of values, measured in terms of standards from the mean.

The z-score is given as

z = \dfrac{x-\mu }{s}\\

x = 29

s = 3.6

z = 1.5

Then the mean will be

1.5 = \dfrac{29 - \mu }{3.6}\\\\\mu = 29 - 5.4\\\\\mu = 23.6 \approx 24

More about the z-score link is given below.

brainly.com/question/15016913

7 0
2 years ago
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Question 2) The measures of the angles of a triangle
Nana76 [90]

Answer:

15 18 21 are the answer hope it's useful

5 0
3 years ago
Let T: Rn → Rn be an invertible linear transformation, and let S and U be functions from Rn into Rn such that
ipn [44]

Answer:

Follows are the solution to this question:

Step-by-step explanation:

T: 1 \ R^n \to  1 \ R^n is invertible lines transformation

S[T(x)]=x \ and \ V[T(x)]=x \\\\t'x \  \varepsilon\ 1 R^n\\\\

T is invertiable linear transformation means that is  

T(x) =A x \\\\ where \\\\ A= n \times n \ \ matrix

and \ det(A) \neq 0 \ \ that \ is \ \ A^{-1} \ \ exists

Let

V \varepsilon\  a\  R^{n} \ consider \ \ u= A^{-1} v \varepsilon 1 R^n\\\\T(u)= A(A^{-1} v)=(A \ A^{-1}) \\\\ v= I_{n \times n} \cdot v = v

so,  

s[T(u)]=v[T(u)]\\\\s(v)=v(v) \ \  \forall \ \ v \ \ \varepsilon \ \ 1 R^n

7 0
3 years ago
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