The answer to your question would be 'A'
Answer:
Will's age = 9 years
Bill's age = 11years
Step-by-step explanation:
Let will age = x
Bill = x +2 since he is 2 years older
x(x+2) = 5( x +x+2) - 1
Opening brackets
x² + 2x = 5(2x + 2) - 1
x² + 2x = 10x + 10 - 1
x² + 2x = 10x + 9
Collect like terms
x² + 2x - 10x - 9 = 0
x² - 8x - 9 = 0
Solve quadratically using factorisation method by finding two factors of +9 that can add up to give -8, the coefficient of x.
The factors are -9 and +1
x² + x - 9x - 9 = 0
x(x + 1) -9( x +1)
x+1) (x -9) =0
x + 1 = 0 or x -9 =0
x = -1 or 9
Age can not be negative
Therefore,
Will's age = 9 years
Bill's age = x+2 = 9+2 = 11years
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Plug in the given values and you'll see its option 2.
x=0 , f(x) = 0^2 + 1 = 1
x = 1 , f(x) = 1^2 + 1 = 2
x = 2, f(x) = 2^2 + 1 = 5
Answer:
a. 1 263 888
b. 130 701
c. 72 years
Step-by-step explanation:
a. The differential equation applies here.
Let the quantity increase for a certain time be given by Q(t)
Every unity of time, the quantity increases by 
so that after the time t, the quantity remaining will be given by:
In a similar manner, the quantity R(t) decreases at a rate given by the following expression:
and after the time , t the quantity of R remaining will be given by:
a. To find the population of humans in 1953
1993 - 1953 = 40 years = t
Q(40) = Q×
Q = 1 263 888.44
≈ 1 263 888
b. For bear population in 1993:
t = 40
R(40) = 
b = 130 700. 889
≈130 701
c. time taken for black bear population number less than 100 is given by:
130 = 11000×
solving using natural logarithms gives t = 72.72666
= 72 years Ans
Then second integer is n+2 <--------
n + n + 2 = 24
2n = 22
n = 11
