Q(–1, a) is 4 5 units away from P(3, –2). Find all possible values of a

Mathematics

1 answer:

Natali [406]3 years ago

5 0

Answer:

Step-by-step explanation:

Using the formula for calculating the distance between 2 points.

D = √(x2-x1)²+(y2-y1)²

Given

D = 45 units

The coordinates Q(–1, a) and P(3,2)

45 = √(3-(-1))²+(-2-a)²

45 = √4²+(-2-a)²

45 = √16+(-2-a)²

45² = 16+(-2-a)²

45² = 16+4+4a+a²

45² = 20+4a+a²

a²-4a+20-2025 = 0

a²+4a-2005 = 0

a = -4±√16+4(2005)/2

a = -4±√16+8020/2

a = -4±√8036/2

a = -4±90/2

a = -4+90/2

a = 86/2

a = 43

The possible values of a is 43

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