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ohaa [14]
3 years ago
11

Solve for t.

Mathematics
1 answer:
STALIN [3.7K]3 years ago
8 0

Step-by-step explanation:

12gt^2=19\qquad\text{divide both sides by}\ 12g\\\\t^2=\dfrac{19}{12g}\to t=\sqrt{\dfrac{19}{12g}}

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Please find the surface area of the sphere. Round your answer to the nearest hundredth.
Elenna [48]

Surface area = \frac{4}{3} \pi r^{3} = \frac{4}{3} x 3.14 x 3 x 3 x 3 = 3.14 x 4 x 3 x 3 = 113.04 yd^2 = approx. 113.1 yd^2

4 0
4 years ago
Why and when do we cross multiply in algebra?
Nataly [62]

Answer:

You cross multiply to solve for a variable. You cross multiply when given a proportion.

4 0
3 years ago
Read 2 more answers
Sandra uses her office fax machine to send fax at the rate of $0.10 per page. She decides to rent a fax machine for $80 a year.
Maksim231197 [3]
Part A: 
 First we define the variable to be used for the problem:
 x: the number of pages that Sandra should fax
 The inequality for rent is:
 0.06x <= 80
 Note that the price will be less than using the fax from the office, since for the same number of pages, we have:
 y = 0.10x
 Answer:
 
an inequality that can be used to calculate the number of pages that Sandra should fax in a year is:
 
0.06x <= 80

 Part B:
 0.06x <= 80
 From here we clear x:
 x <= 80 / 0.06
 x <= 1333.33333
 Nearest whole number
 x <= 1333
 Sandra can use the leased fax for 1333 pages and the cost will be:
 1333 * 0.06 = 79.98 $
 Using the office fax the cost will be:
 1333 * 0.1 = 133.3 $
  Answer:
 
By renting the sara machine, you save:
 
133.3-79.98 = 53.32 $
8 0
3 years ago
Can you please help me out
Taya2010 [7]

The bag contains,

Red (R) marbles is 9, Green (G) marbles is 7 and Blue (B) marbles is 4,

Total marbles (possible outcome) is,

\text{Total marbles = (R) + (G) +(B) = 9 + 7 + 4 = 20 marbles}

Let P(R) represent the probablity of picking a red marble,

P(G) represent the probability of picking a green marble and,

P(B) represent the probability of picking a blue marble.

Probability , P, is,

\text{Prob, P =}\frac{required\text{ outcome}}{possible\text{ outcome}}\begin{gathered} P(R)=\frac{9}{20} \\ P(G)=\frac{7}{20} \\ P(B)=\frac{4}{20} \end{gathered}

Probablity of drawing a Red marble (R) and then a blue marble (B) without being replaced,

That means once a marble is drawn, the total marbles (possible outcome) reduces as well,

\begin{gathered} \text{Prob of a red marble P(R) =}\frac{9}{20} \\ \text{Prob of }a\text{ blue marble =}\frac{4}{19} \\ \text{After a marble is selected without replacement, marbles left is 19} \\ \text{Prob of red marble + prob of blue marble = P(R) + P(B) = }\frac{9}{20}+\frac{4}{19}=\frac{251}{380} \\ \text{Hence, the probability is }\frac{251}{380} \end{gathered}

Hence, the best option is G.

5 0
1 year ago
Subtract 3x + 2 from 8x + 9.​
kirill115 [55]

Answer:

5x+7

Step-by-step explanation:

Subtract like terms

(8x+9)-(3x+2)

8x-3x=5x

9-2=7

5x+7 should be your answer I believe

3 0
3 years ago
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