This must be on the moon as the acceleration due to gravity in this equation must be around 1/8 that on earth. :) Anyway...
h=-2t^2+9t+11
A)
dh/dt=-4t+9, when velocity, dh/dt=0, it is the maximum height reached
dh/dt=0 only when 4t=9, t=2.25 seconds
h(2.25)=21.125 ft (21 1/8 ft)
B)
As seen in A), the time of maximum height was 2.25 seconds after the squirrel jumped.
C)
The squirrel reaches the ground when h=0...
0=-2t^2+9t+11
-2t^2-2t+11t+11=0
-2t(t+1)+11(t+1)=0
(-2t+11)(t+1)=0, since t>0 for this problem...
-2t+11=0
-2t=-11
t=5.5 seconds.
Answer:
<h2>y = 3.5x - 2</h2>
Step-by-step explanation:
The slope-intercept form of an equation of a line:
<h3>y = mx + b</h3>
m - slope
b - y-intercept
We have y-intercept b = -2. Substitute:
<h3>y = mx - 2</h3>
We have the point (4, 12) → x = 4, y = 12. Put them in the equation:
12 = 4m - 2 <em>add 2 to both sides</em>
14 = 4m <em>divide both sides by 4</em>
14/4 = m → m = 3.5
Volume of a triangular pyramid is v=1/3AH so the answer is 8
Answer: It should be 18...(Multiple of 9)
Step-by-step explanation:
Answer: it’s the third one
Step-by-step explanation:
It is
